有没有办法在 C 中将字符串拆分为多个字符？

发布于 2024-11-30 00:07:22 字数 236 浏览 0 评论 0原文

C 中是否有一种方法可以在分隔符长度超过一个字符的情况下分割字符串（使用 strtok 或任何其他方式）？我正在寻找这样的东西：

char a[14] = "Hello,World!";
char *b[2];
b[0] = strtok(a, ", ");
b[1] = strtok(NULL, ", ");

我希望它不会分割字符串，因为逗号和 W 之间没有空格。有没有办法做到这一点？

原文

Is there a way in C to split a string (using strtok or any other way) where the delimiter is more than one character in length? I'm looking for something like this:

char a[14] = "Hello,World!";
char *b[2];
b[0] = strtok(a, ", ");
b[1] = strtok(NULL, ", ");

I want this to not split the string because there is no space between the comma and the W. Is there a way to do that?

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染墨丶若流云 2024-12-07 00:07:22

您可以重复调用 substr 来查找出现的情况边界字符串并沿着结果分割。找到结果后，将指针前进子字符串的长度并再次搜索。

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掩耳倾听 2024-12-07 00:07:22

您可以使用 char * strstr(const char *haystack, const char *needle) 在字符串中定位分隔符字符串。

char a[14] = "Hello,World!";
char b[2] = ", ";
char *start = a;
char *delim;
do {
    delim = strstr(start, b);
    // string between start and delim (or end of string if delim is NULL).
    start = delim + 2; // Use lengthof your b string.
} while (delim);

You can use char * strstr(const char *haystack, const char *needle) to locate your delimiter string within your string.

char a[14] = "Hello,World!";
char b[2] = ", ";
char *start = a;
char *delim;
do {
    delim = strstr(start, b);
    // string between start and delim (or end of string if delim is NULL).
    start = delim + 2; // Use lengthof your b string.
} while (delim);

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情仇皆在手 2024-12-07 00:07:22

也许是这样的？不保证可以编译。 ;)

char* strstrtok(char *haystack, char *needle) {
    static char *remaining = null;
    char *working;

    if(haystack)
         working = haystack;
    else if(remaining)
         working = remaining;
    else
         return NULL;

    char *result = working;
    if(result = strstr(working, needle))
        remaining = working + strlen(needle) + 1;

    return result;
}

Something like this maybe? No guarantees that this compiles. ;)

char* strstrtok(char *haystack, char *needle) {
    static char *remaining = null;
    char *working;

    if(haystack)
         working = haystack;
    else if(remaining)
         working = remaining;
    else
         return NULL;

    char *result = working;
    if(result = strstr(working, needle))
        remaining = working + strlen(needle) + 1;

    return result;
}

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