从 C++ 传递结构CLI 到非托管代码
我有一个具有以下定义的非托管代码，
void Load(const somestruct& structinst)
{
//dosomething.
}
我想将一个结构从 CLI 传递到非托管代码中的此方法作为引用，并在 CLI 中取回该结构。
我尝试在 CLI 中创建一个结构 as
[StructLayout(LayoutKind::Sequential, CharSet = CharSet::Ansi, Pack = 2)]
ref struct TEST
{
[MarshalAs(UnmanagedType::SysInt)]
int k;
};
并尝试将结构传递为 as
CLIWrapperClass::WrapperMethod()
{
TEST test;
this->NativeClassInstance->Load(test);
}
并收到类似 error C2664: 'NativeClass::Load' : Cannot conversionparameter 1 from 'Namespace::WrapperClass::TEST' to 'NativeClass 的错误::somestruct&'
我将如何实现这一目标？
I have an unmanaged code that has the following definition,
void Load(const somestruct& structinst)
{
//dosomething.
}
I want to pass a structure from CLI to this method in the unmanaged code as a ref and get back the structure in CLI.
I tried creating a struct in CLI as
[StructLayout(LayoutKind::Sequential, CharSet = CharSet::Ansi, Pack = 2)]
ref struct TEST
{
[MarshalAs(UnmanagedType::SysInt)]
int k;
};
and tried passing the struct as
CLIWrapperClass::WrapperMethod()
{
TEST test;
this->NativeClassInstance->Load(test);
}
and am getting an error like error C2664: 'NativeClass::Load' : cannot convert parameter 1 from 'Namespace::WrapperClass::TEST' to 'NativeClass::somestruct&'
How would I achieve this?
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评论（2）
如果您需要接触 C# 中的
TEST结构，请确保somestruct和TEST结构具有相同基元类型的相同成员相同的尺寸。如果没有，为什么还要使用
StructLayout呢？只需在 C++/CLI 中使用somestruct本身即可，如下所示：If you need to touch the
TESTstructure from C#, please make sure thatsomestructandTESTstructures have the same members of the same primitive type with the same size.If not, why bother with
StructLayout? Just go and usesomestructitself in C++/CLI like:本机代码与垃圾收集器可以声音移动的 .net 类型不兼容。可以使用固定和铸件，但这很脆弱。更好的方法是将数据从托管类型复制到本机结构的实例，然后再复制回来。
native code is incompatible with .net types which can be moved sound by the garbage collector. it's possible to use pinning and a cast, but that's fragile. better is just to copy the data from the managed type to an instance of the native struct and back again.