计算 WPF 中的选择画笔颜色
我注意到，当将 wpf 中的文本框选择设置为红色，并使用颜色选择器验证颜色时，颜色褪色为#FF9999。
我有客户要求的选择画笔的特定颜色。有没有办法计算我应该将 SelectionBrush 设置为什么颜色，以便在选择文本时显示确切的颜色？
目前我需要将选择画笔设置为#6599D1，但设置后，颜色为#C1D6ED。
如何计算起始颜色以便最终颜色是我需要的？
I have noticed when setting the selection of a text box in wpf to red, and using a color picker to verify the color, the color faded to #FF9999.
I have a specific color my client requires for the selection brush. Is there a way to calculate what color i should set the SelectionBrush to so when the text is selected, the exact color is displayed?
Currently I need to have the selection brush as #6599D1, but once set, the color is #C1D6ED.
How can I calculate the starting color so the end color is what I need?
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跟进 HB 的答案，
我过去用以下公式计算了不透明度
，该公式反转为
TextBox默认的Background设置为白色，SelectionOpacity设置为 0.4。正如 HB 所解释的，您无法使用这些默认设置获得颜色，因为红色值将显示为 -130。这给你提供了 3 个选项，更改
Background、更改SelectionOpacity或不执行此操作:)更改
TextBox 背景可能不是问题如果您想要保留选项 2，请更改SelectionOpacity我们不希望红色低于 0，因此
结果
为 0,604，因此您可以使用此
SelectionOpacity值计算出应用不透明度后，SelectionBrush需要设置为#0056B3才能变为#6599D1。以下是
TextBox使用这些值的外观Following up on the answer by H.B.
I've calculated opacity with the following formula in the past
which inverts to
The
TextBoxhas defaultBackgroundset to White andSelectionOpacityset to 0.4.As H.B. explained, you can't achieve your color with these default settings since the Red value will come out as -130. This leaves you with 3 options, Change
Background, changeSelectionOpacityor don't do it :)Changing the
TextBox Backgroundprobably isn't something you wanna do so that leaves option 2, changeSelectionOpacityWe don't want Red to go below 0 so
which gives
This results in 0,604 so with this
SelectionOpacityvalue you can calculate that theSelectionBrushneeds to be set to#0056B3to become#6599D1once the Opacity has been applied.Here's how the
TextBoxlook with these values好问题，但我认为这是不可能的。如果 ControlTemplate 内有一些覆盖，则无法制定一个函数来计算较暗的颜色，然后该颜色最终将成为预期的颜色。
例如，当您输入红色时，即：
255,0,0，您将得到255,153,153，现在需要应用于初始颜色的函数需要使红色变暗，这当然只能在红色通道中完成，因为绿色和蓝色已经为零。然而，问题不在于红色通道（最终为 255，因此不受影响），因此对其进行任何更改只会进一步降低颜色饱和度，而不是使其变暗。编辑：为了使其更数学化，选择的透明度应用的函数是：
如果将其应用于颜色的所有通道，您会发现情况确实如此。现在我们如何获得我们想要的值呢？很简单，我们反转函数，就是这样：
太棒了！现在让我们将其应用到您的颜色上：
嗯，我想毕竟不太好。
这个负值正是为什么这并不总是可能的原因，每种颜色的成分低于
153都是不可逆的。Good question but i think this is impossible. If there is some overlay inside the ControlTemplate you cannot formulate a function which calculates a darker colour which then will end up as the intended colour.
e.g. when you input red which is:
255,0,0you get255,153,153, now the function that would need to be applied to your initial colour would need to darken the Red, this of course could only be done in the red channel as green and blue are already zero. The problem is not the red channel however (which ends up as 255 and hence is not affected), so any changes to that will only serve to desaturate the colour even more instead of darkening it.Edit: To make this a bit more mathmatical, the function that is applied by the transparency of the selection is:
If you apply this to all the channels of your colour you will see that this is indeed the case. Now how do we get the values we want? Quite simple, we invert the function, which is this:
Great! Now lets apply that to your colour:
Hmm, not so great after all i suppose.
This negative value is exactly why this is not always possible, every colour which has components below
153is not reversible.