将多个“”合并到一个“”中。 ASP.NET MVC3

发布于 2024-11-29 08:19:18 字数 2199 浏览 0 评论 0原文

我有一个 ASP.NET MVC3 项目。

我想在一个表中插入一些。这些各包含一个

。这些来自位于partialView中的switch()，并渲染到另一个视图中（其中可以包含多个）。

这是partialView：

@foreach (var item in Model)
{
   switch (item.PitlaneId)
       {
           case 1:
                   <td id=a>
                       <div class="drag">
                           Name: @Html.DisplayFor(modelItem => item.Name) <br />
                           Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                       </div>
                   </td>
           break;

           case 2:
                   <td id=b>
                       <div class="drag">
                           Name: @Html.DisplayFor(modelItem => item.Name) <br />
                           Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                       </div>
                   </td>
           break;

           case 3:
                   <td id=c>
                       <div class="drag">
                              Name: @Html.DisplayFor(modelItem => item.Name) <br />
                              Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                          </div>
                   </td>
           break;

           default: break;
       }
}

这个partialView 在这里渲染：

<table title="test" id="testTableID">
   <colgroup> @foreach (var item in Model){<col width="300" />} </colgroup>
   <tbody>
      <tr>
         @{Html.RenderAction("Tasks"); }  @* <--- Here it renders*@
      </tr>
   </tbody>
</table>

当 switch() 多次转到相同的情况时，会出现问题。如果我的 PitlaneId 按以下顺序排列：1,2,2,3；它将在我的表中创建 4 个。在这种情况下，我应该只有 3 个，并且具有相同 PitlaneId=2 的两个

应该位于同一个。 我的意思是具有相同 id 的应该合并在一起。当 PitlaneId 按以下顺序出现时情况相同：1,2,3,2。

原文

I have an ASP.NET MVC3 project.

I want to insert some <td>'s in one table <tr>. These <td>'s contain one <div> each. These comes from a switch() which is in a partialView and renders into another View (where is the <tr> which could contain multiple <td>'s).

This is the partialView:

@foreach (var item in Model)
{
   switch (item.PitlaneId)
       {
           case 1:
                   <td id=a>
                       <div class="drag">
                           Name: @Html.DisplayFor(modelItem => item.Name) <br />
                           Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                       </div>
                   </td>
           break;

           case 2:
                   <td id=b>
                       <div class="drag">
                           Name: @Html.DisplayFor(modelItem => item.Name) <br />
                           Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                       </div>
                   </td>
           break;

           case 3:
                   <td id=c>
                       <div class="drag">
                              Name: @Html.DisplayFor(modelItem => item.Name) <br />
                              Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
                          </div>
                   </td>
           break;

           default: break;
       }
}

And this partialView renders here:

<table title="test" id="testTableID">
   <colgroup> @foreach (var item in Model){<col width="300" />} </colgroup>
   <tbody>
      <tr>
         @{Html.RenderAction("Tasks"); }  @* <--- Here it renders*@
      </tr>
   </tbody>
</table>

The PROBLEM appears when switch() goes to the same case multiple times. If I have PitlaneId in this order: 1,2,2,3; It will create 4 <td>'s in my table. In this case I should have only 3 <td>'s and the two <div>'s with the same PitlaneId=2 should be inside the same <td>. I mean <td>'s with the same id should merge together. Same situation when PitlaneId comes in this order: 1,2,3,2.

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音盲 2024-12-06 08:19:18

这是我让它发挥作用的唯一方法。它看起来很臭，但它提供了您指定的元素的顺序。

@Html.Raw("<table><tr><th>ID 1</th><th>ID 2</th><th>ID 3</th></tr><tr>")

@foreach (int id in Model.OrderBy(p => p.PitlaneID)
    .Select(p => p.PitlaneID).Distinct())
{ 
    switch(id)
    {
        case 1:  
            @:<td id="a">
            break;
        case 2:  
            @:<td id="b">
            break;
        case 3:  
            @:<td id="c">
            break;
        default: break;
    }

    foreach (var item in Model.Where(p => p.ID == id))
    { 
        <div class="drag">
            Name: @Html.DisplayFor(modelItem => item.Name) <br />
            Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
        </div>
    }

    Html.Raw("</td>");
}

@Html.Raw("</tr></table>")

This is the only way I could make it work. It seems smelly, but it provides the order of elements you specified.

@Html.Raw("<table><tr><th>ID 1</th><th>ID 2</th><th>ID 3</th></tr><tr>")

@foreach (int id in Model.OrderBy(p => p.PitlaneID)
    .Select(p => p.PitlaneID).Distinct())
{ 
    switch(id)
    {
        case 1:  
            @:<td id="a">
            break;
        case 2:  
            @:<td id="b">
            break;
        case 3:  
            @:<td id="c">
            break;
        default: break;
    }

    foreach (var item in Model.Where(p => p.ID == id))
    { 
        <div class="drag">
            Name: @Html.DisplayFor(modelItem => item.Name) <br />
            Constrainted: @Html.DisplayFor(modelItem => item.Constrainted) <br />
        </div>
    }

    Html.Raw("</td>");
}

@Html.Raw("</tr></table>")

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