Foreach 循环在分解变量后不会循环..需要帮助
我无法显示数据库中的一行，该行具有以逗号分隔的数组形式的技能列表。完整注释的代码和下面的解释是我到目前为止所做的。非常感谢所有帮助。提前致谢。
// DB Connection here
// Execute Query
$sql = "SELECT id, skills FROM p_info";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
// Delimit array by comma
$myArray = explode(',', $row['skills']);
// Store as array
$myArr = array($myArray);
/**
Assume the value of is skills row in the database is: type 1, type 2, type 3, type 4
i would like to show these values each on a seperate <li> element hence using a loop.
<li> type 1</li>
<li> type 2</li>
<li> type 3</li>
<li> type 4</li>
My guess would be to use foreach loop..but im a little confused how to go about this. Here whats i think logically:
**/
?>
<ul>
<?
foreach ( $myArr as $skills ) {
?>
<li><?=$myArr;?></li>
<?
} // End loop
?>
</ul>
<!-- Can someone tell me what im doing wrong? im fairly new to PHP but im a quick learner. :) -->
I am having trouble showing a row from a database which has a list of skills as an array which is delimited by a commas. Fully annotated code with explanation below is what i've done sor far. All help is much appreciated. Thanks in advance.
// DB Connection here
// Execute Query
$sql = "SELECT id, skills FROM p_info";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);
// Delimit array by comma
$myArray = explode(',', $row['skills']);
// Store as array
$myArr = array($myArray);
/**
Assume the value of is skills row in the database is: type 1, type 2, type 3, type 4
i would like to show these values each on a seperate <li> element hence using a loop.
<li> type 1</li>
<li> type 2</li>
<li> type 3</li>
<li> type 4</li>
My guess would be to use foreach loop..but im a little confused how to go about this. Here whats i think logically:
**/
?>
<ul>
<?
foreach ( $myArr as $skills ) {
?>
<li><?=$myArr;?></li>
<?
} // End loop
?>
</ul>
<!-- Can someone tell me what im doing wrong? im fairly new to PHP but im a quick learner. :) -->
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$myArr = array($myArray);并执行foreach ( $myArray as $skills ) {。您将数组放入一个新数组中，因此当您尝试循环它时，您最终会得到原始数组。
还将
更改为，您正在循环$myArray并将每个部分临时存储在$skills中，$myArray不会改变，因此尝试echo它是没有用的。Remove
$myArr = array($myArray);and doforeach ( $myArray as $skills ) {instead.You are putting your array within a new array, so when you try to loop through it you end up with the original array.
Also change
<?=$myArr;?>to<?=$skills;?>, you are looping through$myArrayand storing every part in$skillstemporarily,$myArraydoesn't change so it's useless trying toechoit.explode已经返回一个数组。将结果包装在数组中将为您提供如下结果：当循环外部数组时，当然您不会获得内部数组的结果。只需摆脱
$myArr = array($myArray)并使用$myArray即可。explodealready returns an array. Wrapping that result in an array will give you something like this:When looping over the outer array, of course you won't get the results of the inner array. Just get rid of
$myArr = array($myArray)and use$myArray.$myArray已经是一个数组。而不是$myArr。这就是数组。)，而是使用$myArrayis already an array.<li><?php echo $skills; ?>instead of$myArr. That's the array.<?) use<?phpinstead不需要执行
$myArr = array($myArray);因为explode()已经返回一个数组。您始终可以对数组或任何其他变量执行
var_dump($myArray)来查看其中的内容。No need to do
$myArr = array($myArray);asexplode()already returns an array.You can always do a
var_dump($myArray)on your array or any other variable to see what's in there.