字符串的枚举的等效项

发布于 2024-11-28 23:58:34 字数 400 浏览 2 评论 0原文

我研究了枚举，它只需要整数输入并返回相应的值。我想实现同样的目标，但我只有字符串作为输入。我想做以下工作 -

enum Types {
"Absolute", //"abs"
"PURE", //"PRE"
"MIXED" //"MXD"
}

可能的陈述可能是 -

string sTpes = Types("abs"); //this should return "Absolute"

或者

string sTpes = Types("MXD"); //this should return "MIXED"

如果不使用枚举，请建议我实现这一目标的可能方法。

谢谢。

原文

I studied enums which expects only integer inputs and returns corresponding value to it.I want to achieve same thing but I only have strings as a input. I want to make following work -

enum Types {
"Absolute", //"abs"
"PURE", //"PRE"
"MIXED" //"MXD"
}

and probable statment could be -

string sTpes = Types("abs"); //this should return "Absolute"

string sTpes = Types("MXD"); //this should return "MIXED"

If not using enums, please suggest me possible ways to achieve this.

Thanks.

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雪落纷纷 2024-12-05 23:58:35

您可以使用 string.hi 中的字符串数组（大小为 2）（可以是该数组，也可以只是字符串；一个用于 C，另一个用于 cpp）。第一个字符串是“abs”，第二个字符串是“absolute”。

例如：

#include <string>

...

string abs[2]; //or a better name that's more relevant to you

abs[0] = "abs";
abs[1] = "absolute";

...

//pass it into the function
cout << abs[1] << endl;

...

you could use a string array (of size 2) from string.h i think (either that or just string; one is for C and other is for cpp). first string is "abs" second is "absolute".

for example:

#include <string>

...

string abs[2]; //or a better name that's more relevant to you

abs[0] = "abs";
abs[1] = "absolute";

...

//pass it into the function
cout << abs[1] << endl;

...

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笑咖 2024-12-05 23:58:34

没有“字符串枚举”，但要从一个值映射到另一个值，您可以使用 std::map ，这是 C++ 平台附带的标准模板：

#include <map>
#include <string>

int main() {
    using std::map;  using std::string;

    map<string, string> ss;
    ss["abs"] = "Absolute";

    const string foo = ss["abs"];
    std::cout << ss["abs"] << ", or " << foo << std::endl;
}

在 C++0x 中，如果如果您想要“安全”访问，如果找不到键类型，则抛出异常，请使用 map::at （实际上，缺少 map::at > 只是当前标准中的一个疏忽）：

    std::cout << ss.at("weird keY");

或检查它是否存在：

    if (ss.find("weird keY")==ss.end())
        std::cout << "key not found\n";

There are no "string-enums", but to map from one value to another, you can use std::map, which is a standard template shipped with C++ platforms:

#include <map>
#include <string>

int main() {
    using std::map;  using std::string;

    map<string, string> ss;
    ss["abs"] = "Absolute";

    const string foo = ss["abs"];
    std::cout << ss["abs"] << ", or " << foo << std::endl;
}

In C++0x, if you want "safe" access that throws an exception if the key-type wasn't found, use map::at (actually, afair, the lack of map::at was just an oversight in the current standard):

    std::cout << ss.at("weird keY");

or check if it exists:

    if (ss.find("weird keY")==ss.end())
        std::cout << "key not found\n";

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黎歌 2024-12-05 23:58:34

如果你正在谈论 c++/cli 你可以使用这个
Hashtable^ openWith = gcnew Hashtable();

    // Add some elements to the hash table. There are no
    // duplicate keys, but some of the values are duplicates.
    openWith->Add("txt", "notepad.exe");
    openWith->Add("bmp", "paint.exe");
    openWith->Add("dib", "paint.exe");
    openWith->Add("rtf", "wordpad.exe");

来自 http://msdn.microsoft.com/fr- fr/library/system.collections.hashtable.aspx#Y4406
否则使用 stdlib 中的映射。

我认为您也可以从 MFC 使用 CMAP，这里有一篇关于它的好文章： http: //www.codeproject.com/KB/architecture/cmap_howto.aspx

if you are talking about c++/cli you could use this
Hashtable^ openWith = gcnew Hashtable();

    // Add some elements to the hash table. There are no
    // duplicate keys, but some of the values are duplicates.
    openWith->Add("txt", "notepad.exe");
    openWith->Add("bmp", "paint.exe");
    openWith->Add("dib", "paint.exe");
    openWith->Add("rtf", "wordpad.exe");

from http://msdn.microsoft.com/fr-fr/library/system.collections.hashtable.aspx#Y4406
else use map from stdlib.

I think you can also use CMAP from MFC, there is a good article about it here : http://www.codeproject.com/KB/architecture/cmap_howto.aspx

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