CakePHP - 关系问题 - Posts.Child属于用户，如何定义？

发布于 2024-11-28 17:46:50 字数 18069 浏览 1 评论 0原文

下面是一个帖子模型，正如您所看到的，我在每个帖子上都有一个“belongsTo”关系，因此用户详细信息也会随帖子一起检索。我还希望 Posts.Children 具有完全相同的行为（请参阅下面的 hasMany 定义）。

问题：

如何将“belongsTo”关系应用到“Posts.Children”（“Posts.Child ownsTo User”）？

<?php
class Post extends AppModel {

    var $name = 'Post';

    var $belongsTo = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'post_owner',
          'fields' => array( "User.id" , "User.first_name" , "User.last_name" )
        )
    );

    // -=> 
    var $hasMany = array(
        'Child' => array(
            'className' => 'Post',
            'foreignKey' => 'parent_id',
        'conditions' => array( "Child.active" => "1" ),
        'limit' => '2',
        'order' => 'time DESC'
        )
    );
}
?>

这是我当前正在使用的 PostsController 代码：

class PostsController extends AppController {    
    var $helpers = array ('Html','Form');
    var $name = 'Posts';

    function index() {
        $conditions = array( "Post.parent_id" => "0" , "Post.active" => "1" );
        $this->set(     'posts', $this->Post->find('all',array(   'conditions'=>$conditions     ))   );
        debug(   $this->Post->find('all',array(   'conditions'=>$conditions  ))   );
}

“如果在帖子控制器中调用 debug($this->Post->Child); ，输出是什么？” 这里是：

原文

Below is a posts model, and as you can see I have a belongsTo relationship on each post, so that the user details are also retrieved with the post.
I would also like the exact same behaviour for the Posts.Children (see the hasMany definition below).

QUESTION:

How do I also apply the belongsTo relationship to the Posts.Children ( Posts.Child belongsTo User )??

<?php
class Post extends AppModel {

    var $name = 'Post';

    var $belongsTo = array(
        'User' => array(
            'className' => 'User',
            'foreignKey' => 'post_owner',
          'fields' => array( "User.id" , "User.first_name" , "User.last_name" )
        )
    );

    // -=> 
    var $hasMany = array(
        'Child' => array(
            'className' => 'Post',
            'foreignKey' => 'parent_id',
        'conditions' => array( "Child.active" => "1" ),
        'limit' => '2',
        'order' => 'time DESC'
        )
    );
}
?>

And here is the PostsController Code which I am currently using:

class PostsController extends AppController {    
    var $helpers = array ('Html','Form');
    var $name = 'Posts';

    function index() {
        $conditions = array( "Post.parent_id" => "0" , "Post.active" => "1" );
        $this->set(     'posts', $this->Post->find('all',array(   'conditions'=>$conditions     ))   );
        debug(   $this->Post->find('all',array(   'conditions'=>$conditions  ))   );
}

"what's the output if you call debug($this->Post->Child); in the posts controller?"
Here it is:

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南汐寒笙箫 2024-12-05 17:46:50

您将其放入 Children 模型中。

var $belongsTo = array( 'Post' );

顺便说一句，您发布的是模型，而不是控制器。希望这只是一个拼写错误，并且您将其放在正确的位置。

还不清楚您将该模型称为“Child”还是“Children”。 $hasMany 关系使用 Children，但在您说 Posts.Child 的问题中 - 您是否正确设置了词形变化？

编辑：我可能误解了这个问题：如果你想要一个 hasMany 关系，那么你已经拥有了。问题要么出在检索数据的方式上，要么出在关系定义上。

You put it in the Children model.

var $belongsTo = array( 'Post' );

By the way, what you posted is the model, not the controller. Hopefully it's just a typo and you have that in the correct place.

It's also unclear if you call the model "Child" or "Children". The $hasMany relationship is uses Children, but in the question you say Posts.Child -- do you have the inflection set up correctly?

EDIT: I may have misunderstood the question: if you want a hasMany relationship, you already have that. The problem is either in the way you retrieve the data or in the relationship definition.

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