在 PHP 构造函数中传递对 $this 的引用

发布于 2024-11-28 08:51:27 字数 1091 浏览 1 评论 0原文

我有一个名为 Request 的类。在该类中的某个时刻，我使用以下代码创建一个新控制器，并在构造函数中传递 $this：

$controller = new $this->_controllerName($this);

我的控制器构造函数如下：

public function __construct(Request $request) {
    parent::__construct($request);

    // More stuff
}

如果我修改 $request无论是该对象还是其父对象，最初调用它的对象中的值都不会更改。我还尝试将构造函数定义更改为 public function __construct(Request &$request) { （如 php.net），但这也不起作用。我该如何解决这个问题？

提前致谢！

编辑1：正如所询问的一些代码，显示了我对$request所做的事情。该类有一个名为 _response 的公共属性，它还有一个名为 _body 的公共属性。在我的方法之一中，我执行以下操作：

$this->_request->_response->_body = $this->_template->_render();

现在，我需要调用该方法的请求具有相同的 _request 属性，以便我可以获得正文。

我忘了提到我在调用该方法后立即取消了对象的设置，这是一个问题吗？

编辑2：正如下面指出的，它确实有效，但当我从__destruct()函数调用它时，它不知何故不再起作用。为什么会这样呢？

原文

I've got a class called Request. At some point in that class I create a new controller using the following code, passing $this in the constructor:

$controller = new $this->_controllerName($this);

My controller constructor is as follows:

public function __construct(Request $request) {
    parent::__construct($request);

    // More stuff
}

If I modify $request in either this object or its parent object, the values don't change in the object that originally called it. I also tried changing the constructor definition to public function __construct(Request &$request) { (as said on php.net), but that doesn't work either. How can I fix this?

Thanks in advance!

Edit 1: As asked some code that shows what I do with $request. The class has a public property called _response which has a public property called _body. In one of my methods I do the following:

$this->_request->_response->_body = $this->_template->_render();

Now, I need the request from which I called the method to have the same _request property, so that I can get the body.

I forgot to mention that I unset the object right after calling the method, is that a problem?

Edit 2: As pointed out below it does actually work, but it somehow doesn't work anymore when I call it from my __destruct() function. Why is that the case?

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人间☆小暴躁 2024-12-05 08:51:27


class Request{
    public $var= 'a';
    public $_controllerName='b';
    public function x(){
        $controller = new $this->_controllerName($this);
    }
}
class controller{
    public function __construct(Request $req){
        $req->var='xyz';
    }
}


class b extends controller{
    public function __construct(Request $req){
        parent::__construct($req);
        print $req->var;
        $req->var='LOL';
    }
}

$r=new Request();
$r->x();
print "\n";
print $r->var;

所以

xyz
LOL

，在这两种情况下都效果很好


class Request{
    public $var= 'a';
    public $_controllerName='b';
    public function x(){
        $controller = new $this->_controllerName($this);
    }
}
class controller{
    public function __construct(Request $req){
        $req->var='xyz';
    }
}


class b extends controller{
    public function __construct(Request $req){
        parent::__construct($req);
        print $req->var;
        $req->var='LOL';
    }
}

$r=new Request();
$r->x();
print "\n";
print $r->var;

prints