Django CMS 烦人的错误

Question

我在 Django 项目中有一个简单的搜索应用程序，可以在 CMS 管理员中进行搜索。这是生成 URL 的形式：

< form method="get" action="/search">
            < p>< label for="id_q">Search:
            < input type="text" name="q" id="id_q" />
            < input type="submit" value="Submit" />< /p>
        

, this is the URL:

(r'^search/$', 'search.views.search'), 

this is the view:

def search(request):
    query = request.GET['q']
    results = FlatPage.objects.filter(content__icontains=query)
    template = loader.get_template('search/search.html')
    context = Context({ 'query': query, 'results': results })
    response = template.render(context)
    return HttpResponse(response)

, this is the template:

< html>
    < head>
        < title>Search page
    < /head>
    < body>
        < p>You searched for "{{ query }}"; the results are listed below.< /p>
        < ul>
            {% for page in results %}
                < li>< a href="{{ page.get_absolute_url }}">{{ page.title }}< /a>< /li>
            {% endfor %}
        < /ul>
    < /body>
< /html>

but I keep receiving this error :

"Key 'q' not found in < QueryDict: {} >"

. Does anyone why and what can I do?

Answer 1

据推测，当您在提交搜索词之前首次请求该页面时，就会发生此错误 - 显然，在请求中找不到 q 字段。您只需要先检查一下：

def search(request):
    if 'q' in request.GET:
        query = request.GET['q']
        results = FlatPage.objects.filter(content__icontains=query)

Answer 2

当您在提交中发布结果时，您正在使用 request.GET。使用 Daniel 提到的检查并使用 POST 代替：

def search(request):
    if 'q' in request.GET:
      query = request.GET['q']
      results = FlatPage.objects.filter(content__icontains=query)
    else:
      query = ""
      results = None
    template = loader.get_template('search/search.html')
    context = Context({ 'query': query, 'results': results })
    response = template.render(context)
    return HttpResponse(response)        

Answer 3

您可以将该行从 query = request.GET['q'] 更改为 query = request.GET.get('q')

请注意 get( ) 函数...当然这里的其他答案也可以。请参阅类似的问题：

'instancemethod'对象没有属性'__getitem__'