php - 修复文件夹结构的脚本

发布于 2024-11-27 19:35:30 字数 443 浏览 1 评论 0原文

我正在更改在网站后端保存文件的方式，从：

uploads/item/x/subitem/y/document.pdf

其中 x 和 y 是整数 id，将其更改为：

uploads/item/x/subitem/y/report/document.pdf

我还需要更改当前文件夹目录，该目录有超过 1000 条记录。有没有一种好的方法可以在 php 中修复此结构，而无需处理嵌套循环中的每个文件夹，我只需要在文档之前添加另一个文件夹即可。

编辑：

这是我试图找到的命令！

foreach(glob('uploads/item/*/subitem/*/*') as $filePath)

谢谢你们的帮助。

原文

I am changing the way I save files on the back-end of my website from:

uploads/item/x/subitem/y/document.pdf

Where x and y are integer id's, changing it to:

uploads/item/x/subitem/y/report/document.pdf

I need to change the current folder directory as well, which is over 1000 records. Is there a nice way to fix this structure in php without addressing each folder in nested loops, I just need to add another folder before the document.

EDIT:

This was the command I was trying to find!

foreach(glob('uploads/item/*/subitem/*/*') as $filePath)

Thanks for the help guys.

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猫瑾少女 2024-12-04 19:35:30

您是否尝试过 php 的重命名：

rename("uploads/item/x/subitem/y","uploads/item/x/subitem/y/report");

Have you tried php's rename:

rename("uploads/item/x/subitem/y","uploads/item/x/subitem/y/report");

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ㄟ。诗瑗 2024-12-04 19:35:30

// Change the current directory to the folder containing all your data
chdir('uploads/item/x/subitem/y');

// Attempt to create the report directory if it does not already exist
if ((file_exists('report') && is_dir('report')) || mkdir('report'))
{
    // Move every PDF file in the current directory
    foreach (glob('*.pdf') as $File)
    {
        rename($File, 'report/' . $File);
    }
}
else
{
    echo 'ERROR! Directory could not be created.';
}

// Change the current directory to the folder containing all your data
chdir('uploads/item/x/subitem/y');

// Attempt to create the report directory if it does not already exist
if ((file_exists('report') && is_dir('report')) || mkdir('report'))
{
    // Move every PDF file in the current directory
    foreach (glob('*.pdf') as $File)
    {
        rename($File, 'report/' . $File);
    }
}
else
{
    echo 'ERROR! Directory could not be created.';
}

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赠意 2024-12-04 19:35:30

您不能在 y/ 下创建一个文件夹 report/，然后将 y/ 中的所有文件移至 report/?这根本不需要 PHP。

编辑：我的 bash 非常生疏，所以这里可能有很多语法错误。但这是基本思想：

for x in /fullpath/uploads/item/*
do
    for y in uploads/item/$x/subitem/*
    do
        cd /fullpath/uploads/item/$x/subitem/$y
        mkdir report/
        mv * report/
    done
done

Couldn't you just create a folder report/ under y/ and then move all files in y/ into report/? This doesn't require PHP at all.

EDIT: My bash is very rusty so there are probably a lot of syntax errors in here. But this is the basic idea:

for x in /fullpath/uploads/item/*
do
    for y in uploads/item/$x/subitem/*
    do
        cd /fullpath/uploads/item/$x/subitem/$y
        mkdir report/
        mv * report/
    done
done

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