Django 如何根据选择字段验证请求的 URL？

发布于 2024-11-27 14:37:36 字数 624 浏览 0 评论 0原文

我正在编写的应用程序中的一个模型中有一个选择字段。为了论证起见，它看起来像：

MANUFACTURERS = (
    ('sk','skoda')
    ('vw','volkswagen')
)
class car(models.Model):
    manufacturer = models.CharField(max_length='2', choices=MANUFACTURERS)

现在，我想创建一个视图来列出制造商的所有汽车，我将视图连接起来以将制造商参数作为 URL 的一部分，但问题是验证这个确实是公认的制造商缩写，如“sk”或“vw”。

最初，我经历了一个棘手的过程：导入 MANUFACTURERS 常量，创建缩写列表，并检查给定值是否存在于该列表中。然后迭代 MANUFACTURERS 常量来获取全名。

for manufacturer in MANUFACTURERS:
    manufacturers.append(manufacturer[0])

if url_given_mfn in manufacturers:
    continue
else:
    raise Http404

等等，这非常不优雅——有更好的解决方案吗？

原文

I have a choice field in one of my models in an app I am writing. It looks, for arguments sake, like:

MANUFACTURERS = (
    ('sk','skoda')
    ('vw','volkswagen')
)
class car(models.Model):
    manufacturer = models.CharField(max_length='2', choices=MANUFACTURERS)

Now, I want to create a view to list all the cars by a manufacturer, I wired up the view to take a manufacturer argument as part of the URL, but the issue is then validating that this is indeed an accepted manufacturer abbreviation as per 'sk', or 'vw'.

Initially I went through a hacky process of importing the MANUFACTURERS constant, creating a list of the abbreviations, and checking that the given value exists in that list. Then iterating the MANUFACTURERS constant to get the full name.

for manufacturer in MANUFACTURERS:
    manufacturers.append(manufacturer[0])

if url_given_mfn in manufacturers:
    continue
else:
    raise Http404

etc. this is pretty inelegant - is there a better solution?

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荒人说梦 2024-12-04 14:37:36

我要做的是从可能的制造商中创建一个字典，例如：

from mymodel import MANUFACTURERS
mdict = dict(MANUFACTURERS)


def myview(request, manufacturer):
    if not (manufacturer in mdict):
        raise Http404

    #--> do what you need to do

这样您就可以查看键（缩写），如果您想检索值，只需执行以下操作：

mdict[manufacturer]

您也可以在模型中执行该字典如果您愿意，只需导入即可。

What I would do is to make a dict out of the possible manufacturers, for example:

from mymodel import MANUFACTURERS
mdict = dict(MANUFACTURERS)


def myview(request, manufacturer):
    if not (manufacturer in mdict):
        raise Http404

    #--> do what you need to do

This way you are looking on the keys (the abrevation) and if you want to retrieve the value just do:

mdict[manufacturer]

You could do the dict in the model too and just import it if you like.

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风尘浪孓 2024-12-04 14:37:36

我建议你使用 Django 表单。

from django.forms.widgets import RadioSelect
from model import MANUFACTURERS
class manufacturerTypeForm(forms.Form):
    manufacturer = forms.ChoiceField(required = True, label= 'License Type', widget=RadioSelect(), choices=MANUFACTURERS)

因此，您必须验证表单。如果验证为 True，只需保存它，否则显示错误消息。

I will suggest you to use Django form for that.

from django.forms.widgets import RadioSelect
from model import MANUFACTURERS
class manufacturerTypeForm(forms.Form):
    manufacturer = forms.ChoiceField(required = True, label= 'License Type', widget=RadioSelect(), choices=MANUFACTURERS)

so in view you have to just validate the form.If validate True just save it other wise show errot message.

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