使用 Sql Server 2005 过滤自下而上的递归 CTE
我试图从下往上查询单个数据库表中的数据层次结构(我不想包括由于权限而没有特定类型孩子的父母)。架构和示例数据如下:
create table Users(
id int,
name varchar(100));
insert into Users values (1, 'Jill');
create table nodes(
id int,
name varchar(100),
parent int,
nodetype int);
insert into nodes values (1, 'A', 0, 1);
insert into nodes values (2, 'B', 0, 1);
insert into nodes values (3, 'C', 1, 1);
insert into nodes values (4, 'D', 3, 2);
insert into nodes values (5, 'E', 1, 1);
insert into nodes values (6, 'F', 5, 2);
insert into nodes values (7, 'G', 5, 2);
create table nodeAccess(
userid int,
nodeid int,
access int);
insert into nodeAccess values (1, 1, 1);
insert into nodeAccess values (1, 2, 1);
insert into nodeAccess values (1, 3, 1);
insert into nodeAccess values (1, 4, 1);
insert into nodeAccess values (1, 5, 1);
insert into nodeAccess values (1, 6, 0);
insert into nodeAccess values (1, 7, 1);
with Tree(id, name, nodetype, parent)
as
(
select n.id, n.name, n.nodetype, n.parent
from nodes as n
inner join nodeAccess as na on na.nodeid = n.id
where na.access =1 and na.userid=1 and n.nodetype=2
union all
select n.id, n.name, n.nodetype, n.parent
from nodes as n
inner join Tree as t on t.parent = n.id
inner join nodeAccess as na on na.nodeid = n.id
where na.access =1 and na.userid=1 and n.nodetype=1
)
select * from Tree
产量:
id name nodetype parent
4 D 2 3
7 G 2 5
5 E 1 1
1 A 1 0
3 C 1 1
1 A 1 0
如何才能在结果集中不包含重复项?针对实际表的查询在最低级别有更多的节点,因此父节点有更多的重复项。该解决方案至少需要与 SQL Server 2005 配合使用。
提前致谢!
I'm trying to query a hierarchy of data in a single database table from the bottom up (I don't want to include parents that don't have a particular type of child due to authorities). The schema and sample data are as follows:
create table Users(
id int,
name varchar(100));
insert into Users values (1, 'Jill');
create table nodes(
id int,
name varchar(100),
parent int,
nodetype int);
insert into nodes values (1, 'A', 0, 1);
insert into nodes values (2, 'B', 0, 1);
insert into nodes values (3, 'C', 1, 1);
insert into nodes values (4, 'D', 3, 2);
insert into nodes values (5, 'E', 1, 1);
insert into nodes values (6, 'F', 5, 2);
insert into nodes values (7, 'G', 5, 2);
create table nodeAccess(
userid int,
nodeid int,
access int);
insert into nodeAccess values (1, 1, 1);
insert into nodeAccess values (1, 2, 1);
insert into nodeAccess values (1, 3, 1);
insert into nodeAccess values (1, 4, 1);
insert into nodeAccess values (1, 5, 1);
insert into nodeAccess values (1, 6, 0);
insert into nodeAccess values (1, 7, 1);
with Tree(id, name, nodetype, parent)
as
(
select n.id, n.name, n.nodetype, n.parent
from nodes as n
inner join nodeAccess as na on na.nodeid = n.id
where na.access =1 and na.userid=1 and n.nodetype=2
union all
select n.id, n.name, n.nodetype, n.parent
from nodes as n
inner join Tree as t on t.parent = n.id
inner join nodeAccess as na on na.nodeid = n.id
where na.access =1 and na.userid=1 and n.nodetype=1
)
select * from Tree
Yields:
id name nodetype parent
4 D 2 3
7 G 2 5
5 E 1 1
1 A 1 0
3 C 1 1
1 A 1 0
How can I not include the duplicates in the result set? The queries against the real tables have many more nodes at the lowest levels and hence many more duplicates of the parent nodes. The solution needs to work with at least SQL Server 2005.
Thanks in advance!
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最简单(不一定是最有效)的解决方案:
这会更改示例输出的顺序,因为
DISTINCT
运算符实现排序。如果那里有一些故意排序,我无法检测到它,但如果您知道所需的顺序,则可以添加ORDER BY
。The simplest (not necessarily the most efficient) solution:
This changes the order from your sample output because the
DISTINCT
operator implements a sort. If there is some intentional ordering there I cannot detect it but you can add anORDER BY
if you know the order you want.