tsql - 设置顺序值而不循环/游标

发布于 2024-11-27 10:12:47 字数 425 浏览 4 评论 0原文

我需要在数据表中设置一个非唯一标识符。这在组内是连续的,即。对于每个组,ID 应从 1 开始,并以 1 为增量递增,直到该组的最后一行。

下表对此进行了说明。 “新 ID”是我需要填充的列。

Unique ID  Group ID  New ID
---------  --------  ------
1          1123      1
2          1123      2
3          1124      1
4          1125      1
5          1125      2
6          1125      3
7          1125      4

有没有什么方法可以在不循环/游标的情况下做到这一点?如果循环/游标是唯一的方法,那么最有效的代码是什么?

谢谢

I need to set a non-unique identifier in a data table. This would be sequential within a group ie. for each group, the ID should start at 1 and rise in incremements of 1 until the last row for that group.

This is illustrated by the table below. "New ID" is the column I need to populate.

Unique ID  Group ID  New ID
---------  --------  ------
1          1123      1
2          1123      2
3          1124      1
4          1125      1
5          1125      2
6          1125      3
7          1125      4

Is there any way of doing this without looping/cursoring? If looping/cursoring is the only way, what would the most efficient code be?

Thanks

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评论(5

娇纵 2024-12-04 10:12:47

一种方法是在带有子查询的 UPDATE...FROM 语句中使用 ROW_NUMBER() OVER(PARTITION BY ... ORDER BY ...) /code> 在 FROM 子句 中。

update MyTable set NewID = B.NewID
from
MyTable as A
inner join (select UniqueID, ROW_NUMBER() over (partition by GroupID order by UniqueID) as NewID from MyTable) as B on B.UniqueID = A.UniqueID

One method is to use ROW_NUMBER() OVER(PARTITION BY ... ORDER BY ...) in an UPDATE...FROM statement with a subquery in the FROM clause.

update MyTable set NewID = B.NewID
from
MyTable as A
inner join (select UniqueID, ROW_NUMBER() over (partition by GroupID order by UniqueID) as NewID from MyTable) as B on B.UniqueID = A.UniqueID
  • MSDN has a good sample to get you started:
  • You need to utilize a subquery in the FROM clause in order to utilize a windows function (Row_Index())
  • Partition By tells the server when to reset the row numbers
  • Order By tells the server which way to order the group's NewID's
回忆追雨的时光 2024-12-04 10:12:47

我同意 Damien 在评论中的观点,但您不需要 JOIN 您可以直接更新 CTE。

;WITH cte AS
(
SELECT [New ID],
       ROW_NUMBER() OVER (PARTITION BY [Group ID] ORDER BY [Unique ID]) AS _NewID
FROM @T       
)
UPDATE cte
SET [New ID] = _NewID

在线演示

I agree with Damien's point in the comments but you don't need a JOIN you can just update the CTE directly.

;WITH cte AS
(
SELECT [New ID],
       ROW_NUMBER() OVER (PARTITION BY [Group ID] ORDER BY [Unique ID]) AS _NewID
FROM @T       
)
UPDATE cte
SET [New ID] = _NewID

Online Demo

彼岸花ソ最美的依靠 2024-12-04 10:12:47

如果您使用的是 SS 2000,请替换为 RowNumber()

SELECT  UniqueID,
        GroupID,
        (SELECT COUNT(T2.GroupID)
        FROM    myTable T2
        WHERE   GroupID <= T1.GroupID) AS NewID
FROM    myTable T1

Alternate to RowNumber() if you're on SS 2000

SELECT  UniqueID,
        GroupID,
        (SELECT COUNT(T2.GroupID)
        FROM    myTable T2
        WHERE   GroupID <= T1.GroupID) AS NewID
FROM    myTable T1
幸福%小乖 2024-12-04 10:12:47

如果您运行的是旧版本的 mssql,此解决方案也适用

--Test table:

DECLARE @t table(Unique_ID int, Group_ID int,   New_ID int)

--Test data:

INSERT @t (unique_id, group_id)
SELECT 1, 1123 UNION ALL SELECT 2, 1123 UNION ALL SELECT 3, 1124 UNION ALL SELECT 4, 1125 UNION ALL SELECT 5, 1125 UNION ALL SELECT 6, 1125 UNION ALL SELECT 7, 1125 

--Syntax:

UPDATE t 
SET new_id = 
    (SELECT count(*) 
    FROM @t 
    WHERE t.unique_id >= unique_id and t.group_id = group_id 
    GROUP BY group_id) 
FROM @t t

--Result:

SELECT * FROM @t 

Unique_ID   Group_ID    New_ID
----------- ----------- -----------
1           1123        1
2           1123        2
3           1124        1
4           1125        1
5           1125        2
6           1125        3
7           1125        4

This solution will also work, if you are running an old version of mssql

--Test table:

DECLARE @t table(Unique_ID int, Group_ID int,   New_ID int)

--Test data:

INSERT @t (unique_id, group_id)
SELECT 1, 1123 UNION ALL SELECT 2, 1123 UNION ALL SELECT 3, 1124 UNION ALL SELECT 4, 1125 UNION ALL SELECT 5, 1125 UNION ALL SELECT 6, 1125 UNION ALL SELECT 7, 1125 

--Syntax:

UPDATE t 
SET new_id = 
    (SELECT count(*) 
    FROM @t 
    WHERE t.unique_id >= unique_id and t.group_id = group_id 
    GROUP BY group_id) 
FROM @t t

--Result:

SELECT * FROM @t 

Unique_ID   Group_ID    New_ID
----------- ----------- -----------
1           1123        1
2           1123        2
3           1124        1
4           1125        1
5           1125        2
6           1125        3
7           1125        4
就是爱搞怪 2024-12-04 10:12:47
SELECT 
    UniqueId,
    GroupID,
    ROW_NUMBER() OVER (PARTITION BY GroupId ORDER BY UniqueId) AS NewIdx
FROM
    ....
SELECT 
    UniqueId,
    GroupID,
    ROW_NUMBER() OVER (PARTITION BY GroupId ORDER BY UniqueId) AS NewIdx
FROM
    ....
~没有更多了~
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