Rails 3：如何使用 gsub 或用“-”替换空白字符？

发布于 2024-11-27 05:17:02 字数 974 浏览 2 评论 0原文

我有一个艺术家模型是名称：字符串。我想要 /users/1/artists/jimi-hendrix/posts 而不是我现在拥有的 /users/1/artists/1/posts

问题是我不认为我可以使用Friendly_id作为艺术家的名字，这是因为我有多个相同的艺术家姓名，但我想使用相同的 slug，例如所有“jimi hendrix”条目都使用 jimi-hendrix。示例：

  /users/3/artists/jimi-hendrix/posts
  /users/55/artists/jimi-hendrix/posts
  /users/106/artists/jimi-hendrix/posts

Friendly_id 使其看起来像这样：（我不能拥有） /用户/3/艺术家/jimi-hendrix/帖子 /用户/55/艺术家/jimi-hendrix--2/posts /users/106/artists/jimi-hendrix--3/posts

所以我想做的是将艺术家姓名参数而不是 id 传递给控制器。但我需要获取名称并将所有空格替换为“-”，然后在控制器中添加回空格，正确吗？

这将是我的链接：（你能做一些像artist.name.gsub！（）这样的事情吗？？）

 <% @artists.each do |artist| %>
    <%= link_to artist.name, user_artist_posts_path(@user, artist.name) %> 
  <% end %>

然后当我将代码返回到控制器时反转它？

定义索引 @name = params(:artist_id).gsub() # ? @帖子= ... .... 或者有人知道如何在Friendly_id

中包含非唯一的slugs，这样如果属性有重复的名称，它就不会附加--2、--3？

原文

I have an Artist model is name:string. and I want /users/1/artists/jimi-hendrix/posts instead of what I have now which is /users/1/artists/1/posts

The problem is I don't think I can use friendly_id for the artist's name, this is because I have multiples of the same artist name but I want to use the same slug, such as jimi-hendrix for all 'jimi hendrix' entries. Example:

  /users/3/artists/jimi-hendrix/posts
  /users/55/artists/jimi-hendrix/posts
  /users/106/artists/jimi-hendrix/posts

Friendly_id makes it looks like this: (which I can't have)
/users/3/artists/jimi-hendrix/posts
/users/55/artists/jimi-hendrix--2/posts
/users/106/artists/jimi-hendrix--3/posts

So what I'm thinking of doing is passing that artist name parameter to the controller instead of the id. But I need to take the name and replace all whitespace with "-" and then add back the whitespace in the controller correct?

This woulds be my link: (can you doing something like artist.name.gsub!() ??)

 <% @artists.each do |artist| %>
    <%= link_to artist.name, user_artist_posts_path(@user, artist.name) %> 
  <% end %>

Then reverse it when I get the code back to the controller?

def index
@name = params(:artist_id).gsub() # ?
@posts = ...
....
end

Or would anyone know how to have non-unique slugs in friendly_id, so it doesn't append the --2, --3 if the attribute has a duplicate name?

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七禾 2024-12-04 05:17:02

要 gsub 任何非单词字符：

@name = params[:artist_id].gsub( /\W/, '-' )

To gsub anything that is a non-word-character:

@name = params[:artist_id].gsub( /\W/, '-' )

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那请放手 2024-12-04 05:17:02

您应该能够为此使用范围化的Friendly_id。

这在Friendly_id 3.x 和4.x 中都可用。

例如：在Friendly_id 3.x中你可以

has_friendly_id :name, :use_slug => true, :scope => :user

这样做，在4.x中

extend FriendlyId
friendly_id :name, :use => :scoped, :scope => :user

如果你的user_id是55，你的find语句应该是User.find(55).artists.find(params[:id]) 例如。或Artist.find(params[:id]).where(:user_id => 55)。

没有看到您可能拥有的其他代码（路线/模型/has_many/belongs_to关系）
我无法给你确切的答案。

FriendlyId 4.x 文档 http://rubydoc.info/github/norman/Friendly_id/master/框架

FriendlyId 3.2.1.1指南https://github.com/norman/friend_id/blob/a9505acb68c56719d8225ccb09b5840e26be2783/Guide.md

You should be able to use scoped friendly_id's for this.

This is available in both friendly_id 3.x and 4.x.

eg: in friendly_id 3.x you can do

has_friendly_id :name, :use_slug => true, :scope => :user

and in 4.x

extend FriendlyId
friendly_id :name, :use => :scoped, :scope => :user

If your user_id is 55, your find statements should then be User.find(55).artists.find(params[:id]) for example. OR Artist.find(params[:id]).where(:user_id => 55).

Without seeing other code you may have (routes / models / has_many / belongs_to relationships)
I can't give you an exact answer.

FriendlyId 4.x docs http://rubydoc.info/github/norman/friendly_id/master/frames

FriendlyId 3.2.1.1 Guide https://github.com/norman/friendly_id/blob/a9505acb68c56719d8225ccb09b5840e26be2783/Guide.md

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