如何从 Java 应用程序中的 Main 方法运行线程？

发布于 2024-11-27 04:32:19 字数 565 浏览 1 评论 0原文

我相信 static main 方法中使用的变量也应该是 static 。问题是我根本无法在此方法中使用 this 。如果我没记错的话，我必须使用 commnad myThread = new ThraD(this) 启动线程。

下面的代码会产生错误，因为我在线程启动中使用了 this 。我在这里做错了什么？

package app;

public class Server implements Runnable{

    static Thread myThread;


    public void run() {
        // TODO Auto-generated method stub  
    }

    public static void main(String[] args) {
        System.out.println("Good morning");

        myThread = new Thread(this);



    }


}

原文

I believe variables used in static main method should be also static as well.
The problem is that I cannot use this in this method at all. If I remember correctly, I have to initiate thread with commnad myThread = new ThreaD(this).

The below codes produces an error because I used this in thread initiation.
What have I done wrong here?

package app;

public class Server implements Runnable{

    static Thread myThread;


    public void run() {
        // TODO Auto-generated method stub  
    }

    public static void main(String[] args) {
        System.out.println("Good morning");

        myThread = new Thread(this);



    }


}

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雪落纷纷 2024-12-04 04:32:19

你不能使用 this 因为 main 是一个静态方法，this 引用当前实例并且没有。您可以创建一个可传递到线程中的 Runnable 对象：

myThread = new Thread(new Server());
myThread.start();

这将导致您在 Server 类的 run 方法中放入的任何内容都由 myThread 执行。

这里有两个独立的概念，线程和可运行。 Runnable指定需要完成什么工作，Thread是执行Runnable的机制。尽管 Thread 有一个可以扩展的 run 方法，但您可以忽略它并使用单独的 Runnable。

You can't use this because main is a static method, this refers to the current instance and there is none. You can create a Runnable object that you can pass into the thread:

myThread = new Thread(new Server());
myThread.start();

That will cause whatever you put in the Server class' run method to be executed by myThread.

There are two separate concepts here, the Thread and the Runnable. The Runnable specifies what work needs to be done, the Thread is the mechanism that executes the Runnable. Although Thread has a run method that you can extend, you can ignore that and use a separate Runnable.

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放低过去 2024-12-04 04:32:19

将 new Thread(this) 更改为 new Thread(new Server())：

package app;

public class Server implements Runnable{

    static Thread myThread;


    public void run() {
        // TODO Auto-generated method stub  
    }

    public static void main(String[] args) {
        System.out.println("Good morning");

        myThread = new Thread(new Server());



    }


}

Change new Thread(this) to new Thread(new Server()):

package app;

public class Server implements Runnable{

    static Thread myThread;


    public void run() {
        // TODO Auto-generated method stub  
    }

    public static void main(String[] args) {
        System.out.println("Good morning");

        myThread = new Thread(new Server());



    }


}

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纵情客 2024-12-04 04:32:19

class SimpleThread extends Thread {
    public SimpleThread(String name) {
        super(name);
    }
    public void run() {
        for (int i = 0; i < 10; i++) {
            System.out.println(i + " thread: " + getName());
            try {
                sleep((int)(Math.random() * 1000));
            } catch (InterruptedException e) {}
        }
        System.out.println("DONE! thread: " + getName());
    }
}

class TwoThreadsTest {
    public static void main (String[] args) {
        new SimpleThread("test1").start();
        new SimpleThread("test2").start();
    }
}

class SimpleThread extends Thread {
    public SimpleThread(String name) {
        super(name);
    }
    public void run() {
        for (int i = 0; i < 10; i++) {
            System.out.println(i + " thread: " + getName());
            try {
                sleep((int)(Math.random() * 1000));
            } catch (InterruptedException e) {}
        }
        System.out.println("DONE! thread: " + getName());
    }
}

class TwoThreadsTest {
    public static void main (String[] args) {
        new SimpleThread("test1").start();
        new SimpleThread("test2").start();
    }
}

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