一段时间后全局键盘挂钩没有响应
我使用下面的代码,但几乎没有修改:
class globalKeyboardHook {
public struct keyboardHookStruct {
public int vkCode;
public int scanCode;
public int flags;
public int time;
public int dwExtraInfo;
}
public delegate int keyboardHookProc(int code, int wParam, ref keyboardHookStruct lParam);
public keyboardHookProc hookP;
const int WH_KEYBOARD_LL = 13;
const int WM_KEYDOWN = 0x100;
const int WM_KEYUP = 0x101;
const int WM_SYSKEYDOWN = 0x104;
const int WM_SYSKEYUP = 0x105;
#endregion
public List<Keys> HookedKeys = new List<Keys>();
IntPtr hhook = IntPtr.Zero;
public event KeyEventHandler KeyDown;
public event KeyEventHandler KeyUp;
public globalKeyboardHook() {
hook();
}
~globalKeyboardHook() {
unhook();
}
public void hook() {
IntPtr hInstance = LoadLibrary("User32");
hookP = new keyboardHookProc(hookProc);
hhook = SetWindowsHookEx(WH_KEYBOARD_LL, hookP, hInstance, 0);
}
public void unhook() {
UnhookWindowsHookEx(hhook);
}
public int hookProc(int code, int wParam, ref keyboardHookStruct lParam) {
if (code >= 0) {
Keys key = (Keys)lParam.vkCode;
if (HookedKeys.Contains(key)) {
KeyEventArgs kea = new KeyEventArgs(key);
if ((wParam == WM_KEYDOWN || wParam == WM_SYSKEYDOWN) && (KeyDown != null)) {
KeyDown(this, kea) ;
} else if ((wParam == WM_KEYUP || wParam == WM_SYSKEYUP) && (KeyUp != null)) {
KeyUp(this, kea);
}
if (kea.Handled)
return 1;
}
}
return CallNextHookEx(hhook, code, wParam, ref lParam);
}
[DllImport("user32.dll")]
static extern IntPtr SetWindowsHookEx(int idHook, keyboardHookProc callback, IntPtr hInstance, uint threadId);
[DllImport("user32.dll")]
static extern bool UnhookWindowsHookEx(IntPtr hInstance);
[DllImport("user32.dll")]
static extern int CallNextHookEx(IntPtr idHook, int nCode, int wParam, ref keyboardHookStruct lParam);
[DllImport("kernel32.dll")]
static extern IntPtr LoadLibrary(string lpFileName);
}
有时在几次按键后,“hookProc”不会被调用,就好像我已经“取消挂钩”事件一样,它根本不会捕获任何按键。除非我手动执行,否则如何确保它永远不会取消事件?我如何确保我继续订阅该挂钩?
谢谢。
I am using the code below but with little modification:
class globalKeyboardHook {
public struct keyboardHookStruct {
public int vkCode;
public int scanCode;
public int flags;
public int time;
public int dwExtraInfo;
}
public delegate int keyboardHookProc(int code, int wParam, ref keyboardHookStruct lParam);
public keyboardHookProc hookP;
const int WH_KEYBOARD_LL = 13;
const int WM_KEYDOWN = 0x100;
const int WM_KEYUP = 0x101;
const int WM_SYSKEYDOWN = 0x104;
const int WM_SYSKEYUP = 0x105;
#endregion
public List<Keys> HookedKeys = new List<Keys>();
IntPtr hhook = IntPtr.Zero;
public event KeyEventHandler KeyDown;
public event KeyEventHandler KeyUp;
public globalKeyboardHook() {
hook();
}
~globalKeyboardHook() {
unhook();
}
public void hook() {
IntPtr hInstance = LoadLibrary("User32");
hookP = new keyboardHookProc(hookProc);
hhook = SetWindowsHookEx(WH_KEYBOARD_LL, hookP, hInstance, 0);
}
public void unhook() {
UnhookWindowsHookEx(hhook);
}
public int hookProc(int code, int wParam, ref keyboardHookStruct lParam) {
if (code >= 0) {
Keys key = (Keys)lParam.vkCode;
if (HookedKeys.Contains(key)) {
KeyEventArgs kea = new KeyEventArgs(key);
if ((wParam == WM_KEYDOWN || wParam == WM_SYSKEYDOWN) && (KeyDown != null)) {
KeyDown(this, kea) ;
} else if ((wParam == WM_KEYUP || wParam == WM_SYSKEYUP) && (KeyUp != null)) {
KeyUp(this, kea);
}
if (kea.Handled)
return 1;
}
}
return CallNextHookEx(hhook, code, wParam, ref lParam);
}
[DllImport("user32.dll")]
static extern IntPtr SetWindowsHookEx(int idHook, keyboardHookProc callback, IntPtr hInstance, uint threadId);
[DllImport("user32.dll")]
static extern bool UnhookWindowsHookEx(IntPtr hInstance);
[DllImport("user32.dll")]
static extern int CallNextHookEx(IntPtr idHook, int nCode, int wParam, ref keyboardHookStruct lParam);
[DllImport("kernel32.dll")]
static extern IntPtr LoadLibrary(string lpFileName);
}
Sometimes after a few keypresses "hookProc" doesnt get called, as if i have "unhooked" the event, and it wont capture any keystrokes at all. How can i make sure that it never unhooks the event unless i do it in manually? How can i ensure that i keep subscribing to the hook?
Thank you.
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