Java - 使用多个分隔符时的字符串解析或 split() 错误

发布于 2024-11-27 00:37:54 字数 1134 浏览 0 评论 0原文

好吧，你可能会说这是重复的帖子，但它是不同的。

我正在开发一个程序，该程序正在处理用户指定的某种删除分隔符。如果分隔符只是一个字符（特殊或非特殊），我的程序就可以工作。但是，如果用户输入是字符串，则会从消息字符串中删除分隔符的所有字符。

前任。字符串消息 = "ab\nc[d]e{fMardk1g(h)i}j"; 输出将是：bcefghij 但预期的输出是 abcdefghij

我是使用 Pattern 类的新手，所以我不知道问题出在哪里。

这是有问题的代码（我将其放在测试类中，以便隔离问题）

：

public class ParsingTest {
    public static void main(String[] args) {
        String[] delimiters = { "Mardk1", "\n", "[", "]", "{", "}", "(", ")" };  
        StringBuilder regexp = new StringBuilder("");  
        regexp.append("[");  
        for(String s : delimiters) {  
            regexp.append("[");  
            regexp.append(Pattern.quote(s));  
            regexp.append("]");  
        }  
        regexp.append("]");  

        String message = "ab\nc[d]e{fMardk1g(h)i}j";  
        StringBuilder result = new StringBuilder("");  
        String[] a = message.split(regexp.toString());  
        for(String string : a) {  
            result.append(string);
        }
        System.out.println(result);
        for(String str: a) System.out.print(str);
        System.out.println();
    }
}

原文

Ok, you might say that this is a duplicate post but it is different.

I am working on a program that is working on some kind of deleting delimiters specified by the user. My program is working if the delimiter is only a single character (special or not). However, if the user input is a string, it removes the all characters of the delimiter from the message string.

ex. String message = "ab\nc[d]e{fMardk1g(h)i}j";
output will be : bcefghij
but the expected output is abcdefghij

I'm new in using the Pattern class, so I don't know where the problem lies.

Here's the code in question (I put it in a testing class so I can isolate the problem):

import java.util.regex.Pattern;

public class ParsingTest {
    public static void main(String[] args) {
        String[] delimiters = { "Mardk1", "\n", "[", "]", "{", "}", "(", ")" };  
        StringBuilder regexp = new StringBuilder("");  
        regexp.append("[");  
        for(String s : delimiters) {  
            regexp.append("[");  
            regexp.append(Pattern.quote(s));  
            regexp.append("]");  
        }  
        regexp.append("]");  

        String message = "ab\nc[d]e{fMardk1g(h)i}j";  
        StringBuilder result = new StringBuilder("");  
        String[] a = message.split(regexp.toString());  
        for(String string : a) {  
            result.append(string);
        }
        System.out.println(result);
        for(String str: a) System.out.print(str);
        System.out.println();
    }
}

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好久不见√ 2024-12-04 00:37:54

您使用了错误的分组结构。您正在构建一个像 [xyz] 这样的模式，它将匹配任何单个字符 x、y 或 z。您想要匹配多个完整字符串中的任何一个，因此需要正常的 () 样式分组和交替运算符 (|)。有关更多详细信息，请参阅Pattern 文档。

尝试这个来构建正则表达式：

for(String s : delimiters) {
    // We don't want to start with (|
    if (regexp.length() > 1)
    {
        regexp.append("|");
    }
    regexp.append(Pattern.quote(s));  
}

You're using the wrong kind of grouping construct. You're building a pattern like [xyz] which will match any single character x, y or z. You want to match any of several full strings, so you want the normal () style grouping, and the alternation operator (|). Have a look at the Pattern documentation for more details.

Try this instead to build up the regex:

for(String s : delimiters) {
    // We don't want to start with (|
    if (regexp.length() > 1)
    {
        regexp.append("|");
    }
    regexp.append(Pattern.quote(s));  
}

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