使用 array_push() 帮助
我有一个包含错误数组的变量，
$errors = array();
我还有一个 if 语句，用于返回用户名是否已在输入中输入。
if(isset($_POST['submit'])) {
if(empty($_POST['username'])) {
echo array_push($errors, 'You did not submit a username' );
}
}
我使用 array_push() 在其末尾添加错误消息。我使用 for every 循环来检索所有错误字段的值。虽然我不断获取数组值的数量以及预期的字符串......例如，它会回显“1您没有提交用户名”
foreach($errors as $e) {
echo $e;
echo "<br />\n";
}
是否有只检索所需的字符串？
I have a variable holding an array of errors
$errors = array();
I also have an if statement that returns whether or not a username has been entered in an input.
if(isset($_POST['submit'])) {
if(empty($_POST['username'])) {
echo array_push($errors, 'You did not submit a username' );
}
}
I'm using array_push() to add an error message at the end of it. I'm using a for each loop to retrieve the values of all the error fields. although I keep getting the number of array values as well as just the intended string.... For instance it will echo out "1 You did not submit a username"
foreach($errors as $e) {
echo $e;
echo "<br />\n";
}
is there anyway to retrieve just the required string?
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评论（2）
你有一个额外的回声：
You have an extra echo:
从
echo array_push($errors, 'You did not Submit a username' );中删除echo。这是不需要的，这就是与结果中的 1 相呼应的内容。Remove
echofromecho array_push($errors, 'You did not submit a username' );. It's not needed, and that is what's echoing the 1 in your result.