Javascript if 语句上弹出框

发布于 2024-11-26 20:05:36 字数 1170 浏览 0 评论 0原文

我的代码如下：

//Input Validations 
$result = mysql_query("SELECT * FROM members WHERE `email` = '$insp_email' LIMIT 1" ); 
$exist = mysql_fetch_row($result); 
    if ($exist !==false ) { 
       $errmsg_arr[] = 'That Email is already registered.';
       $errflag = true;
       }
$result = mysql_query("SELECT * FROM members WHERE `login` = '$user_name' LIMIT 1" ); 
$exist = mysql_fetch_row($result); 
    if ($exist !==false ) { 
       $errmsg_arr[] = 'That Username is already registered.';
       $errflag = true;
       }

//If there are input validations, redirect back to the registration form
if($errflag) {
    $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
            $_SESSION['ERROR'] = 'Yes';
    session_write_close();
    header("location: accountinfo.php");
    exit();
}

如果注册页面有任何输入验证，用户将被引导回注册页面。我想做的是当它们被重定向回来时， $_SESSION['ERROR'] 将 = True 。当且仅当该值为 True 时，我才需要一个弹出框来显示错误消息。我是弹出消息的代码。我只是不知道如何让它仅在 if $_SESSION['ERROR'] == 'True' 上加载

<script language="javascript">
alert('<?= $s ?>')
</script>

该代码将显示一条带有 php 变量的消息。我需要帮助才能仅在 $_SESSION['ERROR'] 等于 'True' 时显示消息

谢谢！

原文

My code is as follows:

//Input Validations 
$result = mysql_query("SELECT * FROM members WHERE `email` = '$insp_email' LIMIT 1" ); 
$exist = mysql_fetch_row($result); 
    if ($exist !==false ) { 
       $errmsg_arr[] = 'That Email is already registered.';
       $errflag = true;
       }
$result = mysql_query("SELECT * FROM members WHERE `login` = '$user_name' LIMIT 1" ); 
$exist = mysql_fetch_row($result); 
    if ($exist !==false ) { 
       $errmsg_arr[] = 'That Username is already registered.';
       $errflag = true;
       }

//If there are input validations, redirect back to the registration form
if($errflag) {
    $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
            $_SESSION['ERROR'] = 'Yes';
    session_write_close();
    header("location: accountinfo.php");
    exit();
}

If there are any input validations from the registration page, the user will be directed back to the registration page. What I want to do is when they are redirected back, $_SESSION['ERROR'] will = True. When and only when that is = True, do I want a popup box to display a error message. I the code for the popup message. I just can't figure out how to get it to load only on the if $_SESSION['ERROR'] == 'True'

<script language="javascript">
alert('<?= $s ?>')
</script>

That code will display a message with a php variable. I need help getting the message to display only when the $_SESSION['ERROR'] equals 'True'

Thank you!

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℡Ms空城旧梦 2024-12-03 20:05:36

在你的注册页面的某个地方：

<?php if(isset($_SESSION['ERROR']) && $_SESSION['ERROR']) { ?>
<script type = 'text/javascript'>
//<!--
   alert("I am an error Message.");
//-->
</script>
<?php } ?>

当然，如果JS被禁用，它就不起作用。您也可以添加 noscript 标记，并至少以相同的方式显示错误消息。

Somewhere in your register page:

<?php if(isset($_SESSION['ERROR']) && $_SESSION['ERROR']) { ?>
<script type = 'text/javascript'>
//<!--
   alert("I am an error Message.");
//-->
</script>
<?php } ?>

Of course, it won't work if JS is disabled. You could add in a noscript tag as well and at least display the error message in the same fashion.

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