如何使用命令行编译 Delphi 7 项目组文件 (.bpg)？

发布于 2024-11-26 18:27:43 字数 99 浏览 1 评论 0原文

我将很多项目分组到一个项目组中。所有信息都在project.bpg中。现在我想自动构建它们。

如何使用命令行构建所有项目？

我还在使用Delphi 7。

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相对绾红妆 2024-12-03 18:27:43

我自己从未尝试过，但是这里是一篇德语文章，描述了您可以使用make -f ProjectGroup.bpg 因为 *.bpg 本质上是 makefile。

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爺獨霸怡葒院 2024-12-03 18:27:43

您还可以从命令行或批处理文件运行 Delphi，并将 .bpg 文件名作为参数传递。

编辑：示例（对于 D2007，但可以针对 D7 进行调整）：

===rebuild.cmd（摘录）===

@echo off
set DelphiPath=C:\Program Files\CodeGear\RAD Studio\5.0\bin
set DelphiExe=bds.exe
set LibPath=V:\Library
set LibBpg=Library.groupproj
set LibErr=Library.err
set RegSubkey=BDSClean

:buildlib
echo Rebuilding %LibBpg%...
if exist "%LibPath%\%LibErr%" del /q "%LibPath%\%LibErr%"
"%DelphiPath%\%DelphiExe%" -pDelphi -r%RegSubkey% -b "%LibPath%\%LibBpg%"
if %errorlevel% == 0 goto buildlibok

You can also run Delphi from the command line or a batch file, passing the .bpg file name as a parameter.

Edit: Example (for D2007, but can be adjusted for D7):

=== rebuild.cmd (excerpt) ===

@echo off
set DelphiPath=C:\Program Files\CodeGear\RAD Studio\5.0\bin
set DelphiExe=bds.exe
set LibPath=V:\Library
set LibBpg=Library.groupproj
set LibErr=Library.err
set RegSubkey=BDSClean

:buildlib
echo Rebuilding %LibBpg%...
if exist "%LibPath%\%LibErr%" del /q "%LibPath%\%LibErr%"
"%DelphiPath%\%DelphiExe%" -pDelphi -r%RegSubkey% -b "%LibPath%\%LibBpg%"
if %errorlevel% == 0 goto buildlibok

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木落 2024-12-03 18:27:43

正如我对 Ulrich Gerhardt 答案的评论所说，如果您的项目位于子目录中，则 make project_group.bpg 是无用的。 Make 不会使用相对路径，并且项目将无法正确编译。

我制作了一个 python 脚本来编译每个子目录中的所有 DPR。这是我真正想做的，但我将保留上述答案的标记。虽然它对我没有用，但它确实回答了我的问题。

这是我的compile_all.py 脚本。我相信它可能会对某人有所帮助：

# -*- coding: utf-8 -*-

import os.path
import subprocess
import sys

#put this file in your root dir
BASE_PATH = os.path.dirname(os.path.realpath(__file__)) 
os.chdir(BASE_PATH)

os.environ['PATH'] += "C:\\Program Files\\Borland\\Delphi7\\Bin" #your delphi compiler path
DELPHI = "DCC32.exe"  
DELPHI_PARAMS = ['-B', '-Q', '-$D+', '-$L+']


for root, dirs, files in os.walk(BASE_PATH):
    projects = [project for project in files if project.lower().endswith('.dpr')]
    if ('FastMM' in root ): #put here projects you don't want to compile
        continue
    os.chdir(os.path.join(BASE_PATH, root))
    for project in projects:
        print
        print '*** Compiling:', os.path.join(root, project)
        result = subprocess.call([DELPHI] + DELPHI_PARAMS + [project])
        if result != 0:
            print 'Failed for', project, result
            sys.exit(result)

这种方法的另一个优点是您不需要将新项目添加到 bpg 文件中。如果它在子目录中，它将编译。

As I said as a comment to Ulrich Gerhardt answer, the make project_group.bpg is useless if your projects are in subdirectories. Make won't use relative paths and the projects won't compile correctly.

I've made a python script to compile all the DPRs in every subdirectory. This is what I really wanted to do, but I'll leave the above answer as marked. Although it didn't worked for me, It really answered my question.

Here is my script to compile_all.py . I believe it may help somebody:

# -*- coding: utf-8 -*-

import os.path
import subprocess
import sys

#put this file in your root dir
BASE_PATH = os.path.dirname(os.path.realpath(__file__)) 
os.chdir(BASE_PATH)

os.environ['PATH'] += "C:\\Program Files\\Borland\\Delphi7\\Bin" #your delphi compiler path
DELPHI = "DCC32.exe"  
DELPHI_PARAMS = ['-B', '-Q', '-$D+', '-$L+']


for root, dirs, files in os.walk(BASE_PATH):
    projects = [project for project in files if project.lower().endswith('.dpr')]
    if ('FastMM' in root ): #put here projects you don't want to compile
        continue
    os.chdir(os.path.join(BASE_PATH, root))
    for project in projects:
        print
        print '*** Compiling:', os.path.join(root, project)
        result = subprocess.call([DELPHI] + DELPHI_PARAMS + [project])
        if result != 0:
            print 'Failed for', project, result
            sys.exit(result)

Another vantage of this approach is that you don't need to add new projects to your bpg file. If it is in a subdir, it will compile.

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