hibernate commit：在日志中显示已提交，但实际上没有

发布于 2024-11-26 15:54:26 字数 3230 浏览 1 评论 0原文

请看一下这段代码。 Persist 适用于名为 Candidate 的表，但不适用于另一个名为 verifyLink 的表，而 hibernate 显示它正在保留在日志文件中。请查看下面的日志，在第一种情况下，它显示查询“插入候选”，但在第二种情况下，它不显示查询。怎么了？

protected final void doInTransaction(PersistenceActionWithoutResult action) throws EntityAccessorException {
    EntityManager em = emf.createEntityManager();
    try {
        int status = 0;
        status = userTransaction.getStatus();
        if (Status.STATUS_ACTIVE != status){
            count.incrementAndGet();
            userTransaction.begin();
        }
        action.execute(em);
        System.out.println(em);
        status = userTransaction.getStatus();
        System.out.println("status : " + status);
        if (Status.STATUS_ACTIVE == status) {
            if (0 == count.decrementAndGet()) {
                userTransaction.commit();
                System.out.println("committed : ");
            }
        }
    } catch (Exception e) {
        try {
            userTransaction.rollback();
            System.out.println("rolled back :");
            e.printStackTrace();
        } catch (Exception ex) {
            Logger.getLogger(AbstractEntityAccessor.class.getName()).log(Level.SEVERE, null, ex);
        }
        throw new EntityAccessorException(e);
    } finally {
        System.out.println("transaction close :");
        em.close();
    }
}

当我第一次做某事时

[#|2011-07-25T12:38:40.021+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=61;_ThreadName=Thread-1 ;|状态：0|#]

[#|2011-07-25T12:38:40.093+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=61;_ThreadName=Thread-1 ;|Hibernate：插入候选者（comment、creation_date、currentCompany、current_ctc、cv、 cv_name、dob、email_id、email_id_verified、expected_ctc、first_name、last_name、位置、手机、notice_period、密码、性别、upadte_date、years_of_exp、cand_id）值 (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)|#]

[#|2011-07-25T12:38:40.164+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID= 61;_ThreadName=Thread-1;|已提交：|#]

[#|2011-07-25T12:38:47.159+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=61;_ThreadName=Thread-1 ;|状态：0|#]

[#|2011-07-25T12:38:47.159+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=61;_ThreadName=Thread-1 ;|承诺：|#]

原文

Please have a look at this code. Persist works for a table called Candidate and it does not for another table called VerifyLink, whereas, hibernate shows that it is being persisted in the log file.
Please have a look at the log below, In first case it shows the query, "insert into Candidate", but in second case, it does not show the query. what is wrong ?

protected final void doInTransaction(PersistenceActionWithoutResult action) throws EntityAccessorException {
    EntityManager em = emf.createEntityManager();
    try {
        int status = 0;
        status = userTransaction.getStatus();
        if (Status.STATUS_ACTIVE != status){
            count.incrementAndGet();
            userTransaction.begin();
        }
        action.execute(em);
        System.out.println(em);
        status = userTransaction.getStatus();
        System.out.println("status : " + status);
        if (Status.STATUS_ACTIVE == status) {
            if (0 == count.decrementAndGet()) {
                userTransaction.commit();
                System.out.println("committed : ");
            }
        }
    } catch (Exception e) {
        try {
            userTransaction.rollback();
            System.out.println("rolled back :");
            e.printStackTrace();
        } catch (Exception ex) {
            Logger.getLogger(AbstractEntityAccessor.class.getName()).log(Level.SEVERE, null, ex);
        }
        throw new EntityAccessorException(e);
    } finally {
        System.out.println("transaction close :");
        em.close();
    }
}

When I commit something for the first time

[#|2011-07-25T12:38:40.093+0530|INFO|glassfish3.0.1|javax.enterprise.system.std.com.sun.enterprise.v3.services.impl|_ThreadID=61;_ThreadName=Thread-1;|Hibernate: insert into Candidate (comment, creation_date, currentCompany, current_ctc, cv, cv_name, dob, email_id, email_id_verified, expected_ctc, first_name, last_name, location, mobile, notice_period, password, sex, upadte_date, years_of_exp, cand_id) values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)|#]

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遇到 2024-12-03 15:54:26

我在 userTransaction.begin() 之后添加了 em.joinTransaction() ，如下所示，这似乎已经解决了问题。现在可以了。我得到了提示

if (Status.STATUS_ACTIVE != status){
                count.incrementAndGet();
                userTransaction.begin();
                em.joinTransaction();
            }

I added em.joinTransaction() after userTransaction.begin() as shown below and this seems to have solved the problem. It works now. I got the hint from

if (Status.STATUS_ACTIVE != status){
                count.incrementAndGet();
                userTransaction.begin();
                em.joinTransaction();
            }

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