在state_machine中，如何根据运行事件的结果设置下一个状态？

发布于 2024-11-26 15:30:36 字数 973 浏览 4 评论 0原文

我在我的 Rails3 应用程序中使用 Aaron Pfeifer 的 state_machine gem - 它（仍然）很漂亮。

我有一个事件，其结果在处理后才知道，我想根据结果设置以下状态。此处显示的“明显”方法不起作用：它会引发 ArgumentError: :picked_many is not aknown state value 错误。

根据事件结果设置状态的正确方法是什么？（或者我只是想错了？）

class MyModel < ActiveRecord::Base 
  state_machine :initial => :top do 
    event :pickanumber do
      transition any => any
    end 
    state :picked_zero 
    state :picked_one 
    state :picked_many 
  end 
  def pickanumber(n) 
    self.state = case n 
                 when 0 then :picked_zero 
                 when 1 then :picked_one 
                 else :picked_many 
                 end 
    super
  end 
end

和一个示例运行：

> m = MyModel.create 
=> #<MyModel id: 26, state: "top", ...>
> m.pickanumber(2) 
ArgumentError: :picked_many is not a known state value

原文

I am using Aaron Pfeifer's state_machine gem in my Rails3 app -- it's (still) nifty.

I have a event whose outcome isn't known until it has been processed, and I would like to set the following state based on the outcome. The 'obvious' approach shown here doesn't work: it raises an ArgumentError: :picked_many is not a known state value error.

What's the right way to set the state based on the outcome of an event? (Or am I just thinking about this wrong?)

class MyModel < ActiveRecord::Base 
  state_machine :initial => :top do 
    event :pickanumber do
      transition any => any
    end 
    state :picked_zero 
    state :picked_one 
    state :picked_many 
  end 
  def pickanumber(n) 
    self.state = case n 
                 when 0 then :picked_zero 
                 when 1 then :picked_one 
                 else :picked_many 
                 end 
    super
  end 
end

and a sample run:

> m = MyModel.create 
=> #<MyModel id: 26, state: "top", ...>
> m.pickanumber(2) 
ArgumentError: :picked_many is not a known state value

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停顿的约定 2024-12-03 15:30:36

状态在内部存储为字符串而不是符号。

这应该有效...

def pickanumber(n)
    self.state = case n
                 when 0 then "picked_zero"
                 when 1 then "picked_one"
                 else "picked_many"
                 end
    super
end

State is internally stored as a string and not symbol.

This should work...

def pickanumber(n)
    self.state = case n
                 when 0 then "picked_zero"
                 when 1 then "picked_one"
                 else "picked_many"
                 end
    super
end

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