字典中的字典（作为 plist）

发布于 2024-11-26 14:36:47 字数 761 浏览 1 评论 0原文

我有一个设置如下的 plist：

在此处输入图像描述

正如你所看到的，我在字典中有一本字典：每个父节点都有子节点，子节点本身就是一个字典，其中包含与其关联的图像和徽章。

我陷入困境的部分是如何将其转换为 NSOutlineView 的数据源。

目前我有这个：

NSString *paths = [[NSBundle mainBundle] pathForResource:@"navigationItems" ofType:@"plist"]; 
navigationItems = [[NSMutableDictionary alloc] initWithContentsOfFile:paths];

NSArray *parents = [navigationItems allKeys];

for (NSString *parent in parents) {
    SourceListItem *parentItem = [SourceListItem itemWithTitle:parent identifier:parent];

    NSArray *children = [parent allKeys];

    NSLog(@"%@", children);
}

我打算对子级进行 for 循环，但问题是父级是 NSString 并且你不能 for 循环 NSString ..

那我该怎么办？

非常感谢

原文

I have a plist that is set up like:

enter image description here

As you can see, I have a dictionary within a dictionary: each parent node has children nodes, which themselves are a dictionaryy with images and badges associated with them.

The part I'm stuck at is how to turn this into a datasource for a NSOutlineView..

At the moment I have this:

NSString *paths = [[NSBundle mainBundle] pathForResource:@"navigationItems" ofType:@"plist"]; 
navigationItems = [[NSMutableDictionary alloc] initWithContentsOfFile:paths];

NSArray *parents = [navigationItems allKeys];

for (NSString *parent in parents) {
    SourceListItem *parentItem = [SourceListItem itemWithTitle:parent identifier:parent];

    NSArray *children = [parent allKeys];

    NSLog(@"%@", children);
}

I was going to then do a for loop with children, but the problem is is that parent is a NSString and you can't for loop over a NSString..

So what should I do?

Many thanks

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惯饮孤独 2024-12-03 14:36:47

如果我正确地阅读了您的代码，则 parent 是您的 plist 中包含子字典的字典的键。在访问嵌入的子字典数据之前，您需要获取 parent 在 navigationItems 中引用的字典。例如：

NSString *paths = [[NSBundle mainBundle] pathForResource:@"navigationItems" ofType:@"plist"]; 
navigationItems = [[NSMutableDictionary alloc] initWithContentsOfFile:paths];

NSArray *parents = [navigationItems allKeys];

for (NSString *parent in parents) {
    SourceListItem *parentItem = [SourceListItem itemWithTitle:parent identifier:parent];

    NSDictionary *parentData = [navigationItems objectForKey:parent];
    NSArray *children = [parentData allKeys];

    NSLog(@"%@", children);
}

当您循环访问每个子项的键时，请记住以相同的方式访问每个子项的字典数据。

If I'm reading your code correctly, parent is a key for a dictionary containing child dictionaries in your plist. You need to grab the dictionary that parent refers to in navigationItems before accessing the embedded child dictionary data. For example:

NSString *paths = [[NSBundle mainBundle] pathForResource:@"navigationItems" ofType:@"plist"]; 
navigationItems = [[NSMutableDictionary alloc] initWithContentsOfFile:paths];

NSArray *parents = [navigationItems allKeys];

for (NSString *parent in parents) {
    SourceListItem *parentItem = [SourceListItem itemWithTitle:parent identifier:parent];

    NSDictionary *parentData = [navigationItems objectForKey:parent];
    NSArray *children = [parentData allKeys];

    NSLog(@"%@", children);
}

Remember to access the dictionary data for each of the children in the same manner when you loop through their keys.

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