如何检查两个字符串是否包含相同的字母？

Question

$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";

if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}

我正在寻找什么 if 语句？

Answer 1

我想解决方案可能是考虑以下两个变量：

$textone = "pate";
$texttwo = "tape";

1. 首先，分割字符串，得到两个字母数组：

$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);

请注意，正如 @Mike 在他的评论中指出的那样，而不是使用 preg_split() 就像我第一次做的那样，对于这种情况，最好使用 str_split()：

$arr1 = str_split($textone);
$arr2 = str_split($texttwo);

2. 然后，对这些数组进行排序，使字母按字母顺序排列：

sort($arr1);
sort($arr2);

3. 之后，对数组进行内爆，以创建所有字母均按字母顺序排列的单词：

$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);

4.最后，比较这两个单词：

if ($text1Sorted == $text2Sorted) {
    echo "$text1Sorted == $text2Sorted";
}
else {
    echo "$text1Sorted != $text2Sorted";
}

---

将这个想法转化为比较函数将为您提供以下代码部分：

function compare($textone, $texttwo) {
    $arr1 = str_split($textone);
    $arr2 = str_split($texttwo);

    sort($arr1);
    sort($arr2);

    $text1Sorted = implode('', $arr1);
    $text2Sorted = implode('', $arr2);

    if ($text1Sorted == $text2Sorted) {
        echo "$text1Sorted == $text2Sorted<br />";
    }
    else {
        echo "$text1Sorted != $text2Sorted<br />";
    }
}

并在您的两个单词上调用该函数：

compare("pate", "tape");
compare("pate", "tapp");

将得到以下结果：

aept == aept
aept != appt

Answer 2

使用 === 和 !==

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}else{
    echo "The two strings NOT contain the same letters";
}

或

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}

if ($textone !== $texttwo) {
    echo "The two strings NOT contain the same letters";
}