如何使用 Ruby 中的另一个字符串来分割一个字符串？
假设我有一个类似于以下的句子：
The quick brown fox jumps over the lazy dog
我想切掉之前的所有内容并包括“跳跃”，所以我留下：
over the lazy dog
当前，我获取了我想要删除的部分的索引，然后添加该部分的长度，然后对其进行切片，如下所示：
sentence = "The quick brown fox jumps over the lazy dog"
slice_index = sentence.index("jumps").to_i + sentence.size
sliced_sentence = sentence.slice(slice_index..-1)
是否有更好的方法来实现此目的？
谢谢！
Say I have a sentence similar to the following:
The quick brown fox jumps over the lazy dog
I'd like to slice off everything before and including "jumps", so I am left with:
over the lazy dog
Currently, I get the index of the part I'd like to remove, then add the length of that part to it, and then slice it, as such:
sentence = "The quick brown fox jumps over the lazy dog"
slice_index = sentence.index("jumps").to_i + sentence.size
sliced_sentence = sentence.slice(slice_index..-1)
Is there a better way of achieving this?
Thanks!
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就我个人而言，我喜欢正则表达式解决方案，但是
sentence.split(" Jumps ").last也可以工作。即使有多个“跳转”，
Personally, I like the regex solution, but
sentence.split(" jumps ").lastworks too, even if there are multiple "jumps".
您可以使用正则表达式：
jump是您要查找的单词，(.*)$是字符串末尾之前的所有内容，括号表示第一个捕获组（因此被称为 $1）You could use a regular expression:
jumpis the word you are looking for,(.*)$is everything until the end of the string and the brackets represent the first capturing group (which is therefore referenced as $1)也许不是最好的解决方案，但我会这样做：
split 根据分隔符将 str 分成子字符串，返回这些子字符串的数组。数组索引 1 始终是分隔符之后的部分。如果有多个“跳跃”，则会中断
Perhaps not the best solution but I would do it like so:
split divides str into substrings based on a delimiter, returning an array of these substrings. array index 1 will always be the section after the delimiter. This breaks if there are more than one " jumps "