php：如何将每个项目的日期时间递减到 foreach 中...？

发布于 2024-11-25 22:21:00 字数 448 浏览 2 评论 0原文

...而且不仅仅是一次...

    $now = date("D, d M Y H:i:s O");
    foreach ($items AS $item)
        {

            $currentDate = strtotime($now);
            $pastDate = $currentDate-(60*5);
            $formatDate = date("Y-m-d H:i:s", $pastDate);
            echo "\t\t<item>\n";
            echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;

现在，我希望 formatDate 每次递减 5 分钟，我不希望每个元素都有相同的时间...谢谢

原文

... and not one time only...

    $now = date("D, d M Y H:i:s O");
    foreach ($items AS $item)
        {

            $currentDate = strtotime($now);
            $pastDate = $currentDate-(60*5);
            $formatDate = date("Y-m-d H:i:s", $pastDate);
            echo "\t\t<item>\n";
            echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;

now, i want formatDate decrementing of 5 minutes every time, i don't want the same time for every element... thanks

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深府石板幽径 2024-12-02 22:21:00

你最初的减去（60*5）的想法是完全正确的；您只需要不断从工作值中减去它，而不是按照代码重复从原始值中减去它：

$looptime = time();
foreach ($items AS $item) {
    $looptime -= (60*5);
    $formatDate = date("Y-m-d H:i:s", $looptime);
    echo "\t\t<item>\n";
    echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;
}

Your original idea of subtracting (60*5) was exactly right; you just need to keep subtracting it from a working value, rather than repeatedly subtracting it from the original value as per your code:

$looptime = time();
foreach ($items AS $item) {
    $looptime -= (60*5);
    $formatDate = date("Y-m-d H:i:s", $looptime);
    echo "\t\t<item>\n";
    echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;
}

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帥小哥 2024-12-02 22:21:00

$currentDate = time();
foreach ($items as $item){
    $formatDate = date("Y-m-d H:i:s", $currentDate);
    echo "\t\t<item>\n";
    echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;
    $currentDate = strtotime('-5 minutes', $currentDate);
}

$currentDate = time();
foreach ($items as $item){
    $formatDate = date("Y-m-d H:i:s", $currentDate);
    echo "\t\t<item>\n";
    echo "\t\t\t<pubDate>" . $formatDate . "</pubDate>\n" ;
    $currentDate = strtotime('-5 minutes', $currentDate);
}

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静待花开 2024-12-02 22:21:00

如果您使用 PHP 5.3，则应检查 DateTime。它允许您创建特定时间的对象，并且它有一个 sub() 方法，您可以使用该方法来减少时间。

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孤单情人 2024-12-02 22:21:00

$now = time();
foreach ($items AS $item)
    {
        echo "\t\t<item>\n";
        echo "\t\t\t<pubDate>" . date("Y-m-d H:i:s", $now) . "</pubDate>\n" ;
        echo "\t\t</item>\n";
        $now -= (60*5);
    }

$now = time();
foreach ($items AS $item)
    {
        echo "\t\t<item>\n";
        echo "\t\t\t<pubDate>" . date("Y-m-d H:i:s", $now) . "</pubDate>\n" ;
        echo "\t\t</item>\n";
        $now -= (60*5);
    }

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~没有更多了~