如何使用 preg_replace(); 删除链接？

发布于 2024-11-25 17:59:43 字数 474 浏览 0 评论 0原文

我不确定如何解释这一点，所以我将在我的代码中显示它。

<a href="link.php">First</a> and 
<a href="link.php" class="delete">Second</a> and 
<a href="link.php">Third</a>

如何删除打开的并关闭但不删除其余部分？

我要求 preg_replace(); 并且我不是在寻找 DomDocument 或其他方法来执行此操作。我只想看一下 preg_replace(); 的示例，

它是如何实现的？

原文

I'm not sure how to explain this, so I'll show it on my code.

<a href="link.php">First</a> and 
<a href="link.php" class="delete">Second</a> and 
<a href="link.php">Third</a>

how can I delete opening <a href="link.php" class="delete"> and closing </a> but not the rest?

I'm asking for preg_replace(); and I'm not looking for DomDocument or others methods to do it. I just want to see example on preg_replace();

how is it achievable?

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晨曦慕雪 2024-12-02 17:59:43

仅选择您想要保留的组：

$pattern = '~(<a href="[^"]*" class="delete">)([^<]*)(</a>)~';
//                   1                           2      3
$result = preg_replace($pattern, '$2', $subject);

您可以在 preg_replace 上找到更多示例 手册页。

Only pick the groups you want to preserve:

$pattern = '~(<a href="[^"]*" class="delete">)([^<]*)(</a>)~';
//                   1                           2      3
$result = preg_replace($pattern, '$2', $subject);

You find more examples on the preg_replace manual page.

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黯然 2024-12-02 17:59:43

既然您在评论中要求我展示执行此操作的任何方法，这里就是。

$html =<<<HTML
<a href="link.php">First</a> and 
<a href="link.php" class="delete">Second</a> and 
<a href="link.php">Third</a>
HTML;

$dom = new DOMDocument();
$dom->loadHTML($html);

$xpath = new DOMXPath($dom);

$elems = $xpath->query("//a[@class='delete']");
foreach ($elems as $elem) {
    $elem->parentNode->removeChild($elem);
}

echo $dom->saveHTML();

请注意，即使您只解析了一个片段，saveHTML() 也会保存完整的文档。

从 PHP 5.3.6 开始，您可以添加 $node 参数来指定它应返回的片段 - 类似于 $xpath->query("/*/body")[0] 会起作用。

Since you asked me in the comments to show any method of doing this, here it is.

$html =<<<HTML
<a href="link.php">First</a> and 
<a href="link.php" class="delete">Second</a> and 
<a href="link.php">Third</a>
HTML;

$dom = new DOMDocument();
$dom->loadHTML($html);

$xpath = new DOMXPath($dom);

$elems = $xpath->query("//a[@class='delete']");
foreach ($elems as $elem) {
    $elem->parentNode->removeChild($elem);
}

echo $dom->saveHTML();

Note that saveHTML() saves a complete document even if you only parsed a fragment.

As of PHP 5.3.6 you can add a $node parameter to specify the fragment it should return - something like $xpath->query("/*/body")[0] would work.

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风吹雨成花 2024-12-02 17:59:43

$pattern = '/<a (.*?)href=[\"\'](.*?)\/\/(.*?)[\"\'](.*?)>(.*?)<\/a>/i';
$new_content = preg_replace($pattern, '$5', $content);

$pattern = '/<a (.*?)href=[\"\'](.*?)\/\/(.*?)[\"\'](.*?)>(.*?)<\/a>/i';
$new_content = preg_replace($pattern, '$5', $content);

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戏舞 2024-12-02 17:59:43

$pattern = '/<a[^<>]*?class="delete"[^<>]*?>(.*?)<\/a>/';

$test = '<a href="link.php">First</a> and <a href="url2.html" class="delete">Second</a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a href="url2.html"><b class="delete">seriously</b></a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a href="url2.html" class="delete"><b class="delete">seriously</b></a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a  class="delete" href="url2.html">Second</a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$pattern = '/<a[^<>]*?class="delete"[^<>]*?>(.*?)<\/a>/';

$test = '<a href="link.php">First</a> and <a href="url2.html" class="delete">Second</a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a href="url2.html"><b class="delete">seriously</b></a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a href="url2.html" class="delete"><b class="delete">seriously</b></a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

$test = '<a href="link.php">First</a> and <a  class="delete" href="url2.html">Second</a> and <a href="link.php">Third</a>';
echo preg_replace($pattern, '$1', $test)."\n";

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梨涡 2024-12-02 17:59:43

preg_replace('@<a href="[^"]+" class="delete">(.+?)</a>@', '$1', $html_string);

重要的是要了解这不是一个理想的解决方案。首先，它需要这种精确格式的标记。其次，如果存在嵌套的锚标记（尽管不太可能），那么这将会失败。这些是正则表达式不应用于解析/操作 HTML 的众多原因中的一部分。

preg_replace('@<a href="[^"]+" class="delete">(.+?)</a>@', '$1', $html_string);

It is important to understand this is not an ideal solution. First, it requires markup in this exact format. Second, if there were, say, a nested anchor tag (albeit unlikely) this would fail. These are some of the many reasons why Regular Expressions should not be used for parsing/manipulating HTML.

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~没有更多了~