php 预替换
如何使用 preg_replace，删除所有带有 class="country" 的链接并保留链接的文本。
如何修改下面的preg_replace？
$str = <<<EOT
Long long ago, there was a poor boy named <a href="index1.html">John</a>. Who was living in <a href="index2.html">Liverpoor</a>, a city of <a href="index3.html" class="country">england</a>.
EOT;
$result= preg_replace('/<a(.*?)class="country"(.*?)>(.*?)<\/a>/i','$3',$str);
echo $result;
// I want get the result as: "Long long ago, there was a poor boy named <a href="index1.html">John</a>. Who was living in <a href="index2.html">Liverpoor</a>, a city of england"
How to use preg_replace, remove all the links with class="country" and remain the links' text.
<a href="XXXXXX" class="country">TEXT</a> => TEXT
How to modify the preg_replace below?
$str = <<<EOT
Long long ago, there was a poor boy named <a href="index1.html">John</a>. Who was living in <a href="index2.html">Liverpoor</a>, a city of <a href="index3.html" class="country">england</a>.
EOT;
$result= preg_replace('/<a(.*?)class="country"(.*?)>(.*?)<\/a>/i','$3',$str);
echo $result;
// I want get the result as: "Long long ago, there was a poor boy named <a href="index1.html">John</a>. Who was living in <a href="index2.html">Liverpoor</a>, a city of england"
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这适用于大多数情况：
但请考虑使用 DOM 解析器
This will work with most cases:
but please consider using DOM parser instead