如何将字符串部分与 Objective-C 中的 NSArray 值进行匹配

发布于 2024-11-25 15:10:35 字数 236 浏览 1 评论 0原文

我有以下数组和搜索字符串。

NSArray *values =[NSArray arrayWithObjects:@"abc",@"xyz",@"cba",@"yzx",nil];

NSString *search = @"startcba";

我想在数组元素中搜索字符串的结尾部分。我的预期搜索结果将是@“cba”。请让我知道如何在数组中找到所需的值以进行搜索。

谢谢，

原文

I have following array and search string.

NSArray *values =[NSArray arrayWithObjects:@"abc",@"xyz",@"cba",@"yzx",nil];

NSString *search = @"startcba";

I want to search string's end part within an array elements. My expected search result will be @"cba". Please let me know how to find the desire value in array for giving search.

Thanks,

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絕版丫頭 2024-12-02 15:10:35

您可以使用 NSPredicate 来获取满足您要求的元素。

NSPredicate * predicate = [NSPredicate predicateWithFormat:@" %@ ENDSWITH SELF ", search];
NSArray * searchResults = [values filteredArrayUsingPredicate:predicate];

You can use NSPredicate to get the elements that satisfy your requirement.

NSPredicate * predicate = [NSPredicate predicateWithFormat:@" %@ ENDSWITH SELF ", search];
NSArray * searchResults = [values filteredArrayUsingPredicate:predicate];

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少女情怀诗 2024-12-02 15:10:35

NSPredicates 方法很棒。

这是 rangeOfString 的一种方法：

NSArray *values =[NSArray arrayWithObjects:@"abc",@"xyz",@"cba",@"yzx",nil];

NSString *search = @"startcba";
NSUInteger searchLength = [search length];
NSString *result = nil;

for (NSString *val in values)
{
    NSUInteger valLength = [val length];
    NSRange expectedRange = NSMakeRange(searchLength - valLength, valLength);
    NSRange rng = [search rangeOfString:val];

    if ( rng.location == expectedRange.location && rng.length == expectedRange.length )
    {
        result = val;
        break;
    }
}

The NSPredicates way is great.

Here is an approach with rangeOfString:

NSArray *values =[NSArray arrayWithObjects:@"abc",@"xyz",@"cba",@"yzx",nil];

NSString *search = @"startcba";
NSUInteger searchLength = [search length];
NSString *result = nil;

for (NSString *val in values)
{
    NSUInteger valLength = [val length];
    NSRange expectedRange = NSMakeRange(searchLength - valLength, valLength);
    NSRange rng = [search rangeOfString:val];

    if ( rng.location == expectedRange.location && rng.length == expectedRange.length )
    {
        result = val;
        break;
    }
}

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