使用旧小程序中的deployjava.js 添加参数

Question

我正在使用deployjava.js来部署这个小程序

<script src="http://java.com/js/deployJava.js"></script><script> 
    var attributes = {codebase: '/devel/app/webroot/jpainter/applet',code: 'Painter.class', archive:'painter.jar', width:640, height:480} ; 
    var parameters = {jnlp_href: 'plugin2.jnlp'} ; 
    deployJava.runApplet(attributes, parameters, '1.6'); 
</script>

小程序的API表示要传递这些参数（特别是画布）

我尝试过这个

<script src="http://java.com/js/deployJava.js"></script>
<script> 
var attributes = {codebase: '/devel/app/webroot/jpainter/applet',code:         'Painter.class', archive:'painter.jar', width:640, height:480} ; 
    var parameters = {jnlp_href: 'plugin2.jnlp', gui:'canvas.gui'} ; 
    deployJava.runApplet(attributes, parameters, '1.6'); 
</script>

，显然这是不正确的。让它发挥作用的正确方法是什么？

自然语言处理

<resources> 
    <j2se version="1.4+"/> 
    <jar href="/devel/app/webroot/jpainter/applet/painter.jar"/> 
</resources> 

<applet-desc name="painter" main-class="Painter" width="640" height="480"> 
<param name="plugin2" value="true" />
</applet-desc> 
</jnlp>

Answer 1

如果将来有人偶然发现这一点，当您调用该属性并为其提供 .jar 文件的位置时，不需要同时引用 jnlp。

<script type="text/javascript" src="https://www.java.com/js/deployJava.js"></script>
<script type="text/javascript">
var attributes = {name: 'painter', codebase: BASE_DIR + '/app/webroot/jpainter/applet',code: 'Painter.class', archive:'painter.jar', width:742, height:262} ; 
var parameters = {gui:'canvas.gui', image_width:'740', image_height:'260', stroke:'solid3'};
var version = '1.6' ;
deployJava.runApplet(attributes, parameters, version);
</script>