将 XML 解析为 JSON

发布于 2024-11-25 04:01:35 字数 566 浏览 0 评论 0原文

我有一个 XML 文件,例如

<stock><name>AXL</name><time>19-07</time><price>11.34</price></stock>
<stock><name>AIK</name><time>19-07</time><price>13.54</price></stock>
<stock><name>ALO</name><time>19-07</time><price>16.32</price></stock>
<stock><name>APO</name><time>19-07</time><price>13.56</price></stock>
...............more

如何将其解析为 JSON 结构文件?

I have an XML file, like

<stock><name>AXL</name><time>19-07</time><price>11.34</price></stock>
<stock><name>AIK</name><time>19-07</time><price>13.54</price></stock>
<stock><name>ALO</name><time>19-07</time><price>16.32</price></stock>
<stock><name>APO</name><time>19-07</time><price>13.56</price></stock>
...............more

How can I parse this into JSON structure file?

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蹲在坟头点根烟 2024-12-02 04:01:35

对于简单的解决方案,我推荐 Jackson,这是一个用于生成和读取带有 XML 扩展的 JSON 的 Java 库,因为它可以转换任意复杂的 XML只需几行简单的代码即可将其转换为 JSON。

input.xml

<entries>
  <stock><name>AXL</name><time>19-07</time><price>11.34</price></stock>
  <stock><name>AIK</name><time>19-07</time><price>13.54</price></stock>
  <stock><name>ALO</name><time>19-07</time><price>16.32</price></stock>
  <stock><name>APO</name><time>19-07</time><price>13.56</price></stock>
</entries>

Java 代码

import java.io.File;
import java.util.List;

import org.codehaus.jackson.map.ObjectMapper;

import com.fasterxml.jackson.xml.XmlMapper;

public class Foo
{
  public static void main(String[] args) throws Exception
  {
    XmlMapper xmlMapper = new XmlMapper();
    List entries = xmlMapper.readValue(new File("input.xml"), List.class);

    ObjectMapper jsonMapper = new ObjectMapper();
    String json = jsonMapper.writeValueAsString(entries);
    System.out.println(json);
    // [{"name":"AXL","time":"19-07","price":"11.34"},{"name":"AIK","time":"19-07","price":"13.54"},{"name":"ALO","time":"19-07","price":"16.32"},{"name":"APO","time":"19-07","price":"13.56"}]
  }
}

此演示使用 Jackson 1.7.7 (较新的 1.7.8 也应该可以工作),Jackson XML Databind 0.5.3(尚不兼容)杰克逊1.8) 和 Stax2 3.1.1

For a simple solution, I recommend Jackson, a Java library for generating and reading JSON with an extension for XML, as it can transform arbitrarily complex XML into JSON with just a few simple lines of code.

input.xml

<entries>
  <stock><name>AXL</name><time>19-07</time><price>11.34</price></stock>
  <stock><name>AIK</name><time>19-07</time><price>13.54</price></stock>
  <stock><name>ALO</name><time>19-07</time><price>16.32</price></stock>
  <stock><name>APO</name><time>19-07</time><price>13.56</price></stock>
</entries>

The Java Code:

import java.io.File;
import java.util.List;

import org.codehaus.jackson.map.ObjectMapper;

import com.fasterxml.jackson.xml.XmlMapper;

public class Foo
{
  public static void main(String[] args) throws Exception
  {
    XmlMapper xmlMapper = new XmlMapper();
    List entries = xmlMapper.readValue(new File("input.xml"), List.class);

    ObjectMapper jsonMapper = new ObjectMapper();
    String json = jsonMapper.writeValueAsString(entries);
    System.out.println(json);
    // [{"name":"AXL","time":"19-07","price":"11.34"},{"name":"AIK","time":"19-07","price":"13.54"},{"name":"ALO","time":"19-07","price":"16.32"},{"name":"APO","time":"19-07","price":"13.56"}]
  }
}

This demo uses Jackson 1.7.7 (the newer 1.7.8 should also work), Jackson XML Databind 0.5.3 (not yet compatible with Jackson 1.8), and Stax2 3.1.1.

烟─花易冷 2024-12-02 04:01:35

http://keithchadwick。 wordpress.com/2009/03/14/converting-xml-to-json-with-xsl-part-2/

您尚未指定语言...所以...我还没有比认为“您已经有了 XML,可能您可以访问 xsl/xslt”更具体:

http ://www.w3.org/TR/xslt

http://www.thomasfrank.se/xml_to_json.html

http://keithchadwick.wordpress.com/2009/03/14/converting-xml-to-json-with-xsl-part-2/

You haven't specified language... so... I haven't got more specific on it than to think "you already have XML, probably you have access to xsl/xslt":

http://www.w3.org/TR/xslt

http://www.thomasfrank.se/xml_to_json.html

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