将列表转换为字符串，然后将其返回列表 [Python]
我遇到了一个问题，它是关于从列表转换为字符串来编辑它
我有这些名称的文件文本内容
Roby
Bucky
johan
然后我想在每个文件旁边添加 OK:1
所以我执行了这段代码
Names='a.txt' # here is the names
O=open(Names,'r') # we open the file content the names
iamList=O.readlines() # read the name it would be List !
imSting=str(iamList) # convert it to string
Edit=imSting.replace(r"\n","Ok:1") # Editing by adding
noname=Edit
noname=noname.split()
for PT in noname:
PT.strip('[')
print PT
并得到了这个结果 ['RobyOk:1', '巴基好的：1'， '约翰'] 我想删除这些东西 [ , ' 我尝试了 strip 和 replace('[','')
有什么想法吗？
I got a problem, it's about converting from List to String to edit it
I have file text content these name
Roby
Bucky
johan
Then I want to add beside each one OK:1
so i do this code
Names='a.txt' # here is the names
O=open(Names,'r') # we open the file content the names
iamList=O.readlines() # read the name it would be List !
imSting=str(iamList) # convert it to string
Edit=imSting.replace(r"\n","Ok:1") # Editing by adding
noname=Edit
noname=noname.split()
for PT in noname:
PT.strip('[')
print PT
and i got this result['RobyOk:1',
'BuckyOk:1',
'johan']
i want to delete these thing [ , '
i tried strip and replace('[','')
any ideas ?
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您无需将其转换为字符串即可在每个元素末尾添加
Ok:1。您可以使用 列表理解 来完成此操作，如下所示：
或者，不太花哨，你可以这样做：
注意，
rstrip< /a> 全部剥离字符串末尾的空白，例如换行符，我认为这就是您想要的。You don't need to convert it to a string to add
Ok:1at the end of each element.You could do it with a list comprehension like this:
Alternatively, to be less fancy, you could do this:
Note,
rstripstrips all whitespace, such as newlines, off of the end of the string, which I assume is what you want.解决方案：
我使用了'line.strip()'，因为os.linesep（通常是'\n'）可能与文件中使用的行分隔不同，使每一行仍然带有一个'\n'。
关于你的方法：
因为 iamList 是一个 List，所以由 str(iamList) 创建的该 List 的表示形式
已经包含括号“[”和逗号“,”：
这些是字符串表示的一部分。
print('imSting: ' + imSting)将显示这一点。因此，您可以直接从 imSting 中将 '\n' 替换为 'Ok:1' 并拆分
将新字符串放入列表中的 ', ' 部分：
(imSting.replace(r"\n", 'Ok:1')[2:-2] + 'Ok:1').split("' , '")[2:-2]仅返回 [' 和 '] 之间的字符，从而有效地删除括号。第一个解决方案几乎可以是单行的，并且更容易阅读，因此更加“Pythonic”。
不过，养成阅读后关闭文件的习惯会更好。
solution:
I used 'line.strip()', because the os.linesep (generally '\n') can be different than the line-seperation used in your file, leaving each line still with a '\n'.
About your approach:
Because iamList was a List, the representation of that List created by str(iamList)
already contained the brackets '[' and the commas ',':
these are part of the string representation.
print('imSting: ' + imSting)will show this.So you could have replaced the '\n' by 'Ok:1' right from imSting and spliting the
new string into a list over the ', ' part:
(imSting.replace(r"\n", 'Ok:1')[2:-2] + 'Ok:1').split("', '")The
[2:-2]only returns the characters between [' and '] thus effectively removing the brackets.The first solution could almost be a one-liner and is much easier to read, and therefore much more 'Pythonic'.
However, making a habit of closing the file after reading is better.
你的代码不起作用。最后一行末尾没有换行符，因此其中没有“Ok:1”。
试试这个：
“扩展”版本：
Your code does not work. The last line has no line break at the end, so you don't have "Ok:1" in there.
Try this:
"Expanded" version:
iamList = O.readlines()将为您提供一个列表。您不想将该列表转换为字符串。不惜一切代价避免字符串操作；这是不好的编码习惯。（因此，我也担心您向每个字符串添加
'Ok:1'的原因。）相反，只需执行
[ x+'好的！' for x in yourFile.read().splitlines()]但是，您应该说明为什么要添加“Ok:1”，因为您可能会以错误的方式处理某些事情。 你应该说出你实际上想要做什么。
iamList = O.readlines()will give you a list.You do NOT want to convert that list to a string. Avoid string manipulation at all costs; it's bad coding practice. (For this reason, I am also concerned about the reason you're adding
'Ok:1'to each string.)Instead, just do
[x+' OKAY!' for x in yourFile.read().splitlines()]However you should say why you want to add "Ok:1", because it seems likely you're going about something the wrong way. You should say what you're actually trying to do.