luabind 0.9.1迭代器总是只弹出最后一个对象
全部。我使用 luabind 从 lua 脚本读取数组时遇到了一个奇怪的问题。
lua 脚本如下所示：
root =
{
id = 1,
id = 2,
id = 3
};
c++ 代码如下所示： luabind::object data_root = luabind::globals(L)["root"];
for (luabind::iterator i(data_root), end; i != end; ++i)
{
luabind::object data = *i;
unsigned int id = luabind::object_cast<unsigned int>(data);
std::cout << "id:" << id << std::endl;
}
输出只有：
id:3
我想输出[root]的所有元素，但它只输出最后一个及以上。
谢谢你，杰森:)
all. I got a stranger problem by using luabind to read a array from lua script.
The lua script looks like this:
root =
{
id = 1,
id = 2,
id = 3
};
and the c++ code is looks like this:
luabind::object data_root = luabind::globals(L)["root"];
for (luabind::iterator i(data_root), end; i != end; ++i)
{
luabind::object data = *i;
unsigned int id = luabind::object_cast<unsigned int>(data);
std::cout << "id:" << id << std::endl;
}
the output is only:
id:3
I want to output all the elements of the [root], but it only output the last one and over.
Thank You, Jason :)
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root 没有多个元素，只有一个。您将键
id分配给了三个不同的值，但该键仅存在一次，并且只有一个与之关联的值，因此您基本上只说过root = { id = 3 }.There aren't multiple elements of root, it only has one. You assigned the key
idto three different values, but the key only exists once and only has one value associated with it, so you basically only ever saidroot = { id = 3 }.