帮助 inotify C 脚本
我以前从未使用过 C。该脚本将监听器添加到目录中，并通过回显到终端来通知用户，然后在文件事件发生时退出。我想修改脚本以不退出，而是继续监视文件夹。我认为关键可能是这一行：
length = read( fd, buffer, BUF_LEN );
但我不太明白这里发生了什么。 read() 函数的描述对于那些真正了解 C 的人来说可能会有所帮助：
使用 inotify 很简单：创建一个文件描述符，附加一个或多个监视（监视是一个路径）和事件集），并使用 read() 方法从描述符接收事件信息。 read() 不会消耗稀有的周期，而是会阻塞直到事件发生。
但我不属于这一类。
I've never used C before. this script adds a listener onto a directory and notifies the user by echoing to the terminal and then exiting whenever a file event happens. I want to modify the script to NOT exit but instead continuing monitoring the folder. I think the key might be this line:
length = read( fd, buffer, BUF_LEN );
but I don't really understand what is going on here. The description of the read() function is probably helpful for those who know C really well:
Using inotify is simple: Create a file descriptor, attach one or more watches (a watch is a path and set of events), and use the read() method to receive event information from the descriptor. Rather than burn scarce cycles, read() blocks until events occur.
but I don't fall into that category.
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该程序之所以存在，只是因为一旦它捕获了一个事件，就没有什么可以阻止它到达
exit( 0 );。您可以将从fd = inotify_init();到( void ) close( fd );的所有内容包装在一个循环中，只要您愿意，它就会重新开始。问题不在于
length = read( fd, buffer, BUF_LEN );。该部分只是等待事件发生，并且不会要求程序退出。事实上，main被设计为在一次运行和退出中执行。The program exists simply because nothing stops it from getting to
exit( 0 );once it has caught an event. You could wrap everything fromfd = inotify_init();to( void ) close( fd );in a loop and it will start over as long as you want it to.The problem isn't in
length = read( fd, buffer, BUF_LEN );. That part just waits for an event to happen and it doesn't call for the program to exit. It's really that themainis designed to be executed in one run-through and exit.