可以部分释放一块内存吗？
我正在编写一个内存密集型程序，该程序将有数十个 malloc 数组。当应用程序收到内存不足警告时，我想转储每个数组的下半部分。有什么办法可以做到这一点吗？
我需要某种方法来保留每个数组中一半的内存。显然，如果应用程序内存不足，我无法分配一个较小的数组，将一半的数据复制到其中，然后释放旧数组。是否有任何函数可以释放从指针 A 开始到指针 B 结束的内存块或类似的东西？
I'm writing a very memory intensive program that will have dozens of malloc'd arrays. When the app receives a low memory warning, I want to dump the lower half of each of these arrays. Is there any way to do this?
I need some way that I can preserve half of the memory in each array. Obviously, if the app has low memory, I can't allocate a smaller array, copy half of my data into it, and then free the old array. Is there any function that can free a block of memory starting at pointer A and ending at pointer B or something like that?
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Realloc() 可以将 malloc 内存的尾部部分返回到分配池，但不能将其返回到操作系统。
Realloc() 也无助于解决内存碎片问题，这在内存不足的情况下可能是一个问题。
Realloc() can return the trailing portion of the memory of a malloc back to the allocation pool, but can't return it to the OS.
Realloc() also won't help with memory fragmentation, which is likely a problem in a low-memory situation.
如果它们是 NSMutableArrays，您可以用
[NSNull null]的单个实例替换低端的对象，从而释放所有这些对象。NSNull 类参考
If they are NSMutableArrays, you can replace the objects in the lower end with a single instance of
[NSNull null], thereby releasing all of those objects.NSNull Class Reference