如何使 xsd 元素扩展另一个元素

发布于 2024-11-20 00:24:29 字数 1423 浏览 3 评论 0原文

我有三个不同的 XML 元素，它们具有一些通用标签。

例如：人有姓名、年龄、性别

然后我有经理、员工，它们将共享该人拥有的三个字段，加上经理、员工特定字段，如 managerNo、employeeNo 等。

我可以在 xsd 中编写如下内容吗：

<强>1。声明 Person 元素

<xsd:element name="Person">
        <xsd:annotation>
            <xsd:documentation>Person Request</xsd:documentation>
        </xsd:annotation>
        <xsd:complexType>
            <xsd:sequence>              
                <xsd:element name="personname" type="xsd:string" minOccurs="1" maxOccurs="1" /> 
                <xsd:element name="age" type="xsd:integer" minOccurs="1" maxOccurs="1" />   
            </xsd:sequence>
        </xsd:complexType>
</xsd:element>

使用上述 Person 声明并扩展 Manager 元素：

（只是我正在寻找的想法）

实际上，我试图按照 Java（面向对象）继承来模仿我的模式定义，例如：

public class Person {
   String name;
   int age;

   // getters and setters for above variables go here
}

然后做：

public class Manager extends Person {
   int managerNo;
   String departmentName;
}

public class Employee extends Person {
   int employeeNo;
   String designation;

 // getters/setters and other code goes here
}

我想模仿这个 Java 继承概念在 xsd 中，这样我就可以声明一个基本元素，然后扩展该基本元素，以便其他子元素也继承基本元素的属性。

原文

I have three different XML elements that have some common tags.

For e.g: Person has name, age, sex

Then I have Manager, Employee that would share the three fields the Person has plus Manager, Employee specific fields like managerNo, employeeNo etc.

Can I write something in xsd that would be like this:

1. Declare Person element

<xsd:element name="Person">
        <xsd:annotation>
            <xsd:documentation>Person Request</xsd:documentation>
        </xsd:annotation>
        <xsd:complexType>
            <xsd:sequence>              
                <xsd:element name="personname" type="xsd:string" minOccurs="1" maxOccurs="1" /> 
                <xsd:element name="age" type="xsd:integer" minOccurs="1" maxOccurs="1" />   
            </xsd:sequence>
        </xsd:complexType>
</xsd:element>

Use the above Person declaration and extend the Manager element:

<xsd:element name="Manager" extends="tns:Person"> (just idea of what I am looking for)

In effect, I am trying to mimic my schema definition as per Java (object oriented) inheritance like:

public class Person {
   String name;
   int age;

   // getters and setters for above variables go here
}

then do:

public class Manager extends Person {
   int managerNo;
   String departmentName;
}

public class Employee extends Person {
   int employeeNo;
   String designation;

 // getters/setters and other code goes here
}

I want to mimic this Java inheritance concept in the xsd such that I can declare one base element, and just extend that base element such that other child elements also inherit the properties of base element.

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弱骨蛰伏 2024-11-27 00:24:29

使用：

<xs:extension base="AddressType">

只需在您的 Manager/Employye 模式定义中

<xs:complexType name="Manager">
    <xs:complexContent>
        <xs:extension base="Person"> 
            <xs:sequence>
                <!-- Properties -->
            </xs:sequence>
        </xs:extension>
    </xs:complexContent>
</xs:complexType>

Simply use:

<xs:extension base="AddressType">

in your Manager/Employye schema definition

<xs:complexType name="Manager">
    <xs:complexContent>
        <xs:extension base="Person"> 
            <xs:sequence>
                <!-- Properties -->
            </xs:sequence>
        </xs:extension>
    </xs:complexContent>
</xs:complexType>

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