在 Android 中使用没有 ksoap2 的 SOAP Web 服务

发布于 2024-11-19 23:46:10 字数 146 浏览 9 评论 0原文

在我的Android应用程序中，我使用ksoap2库来使用soap（＆amp; .net）网络服务。它工作正常，但速度非常慢（对于解析、控制、循环和 Base64ToBinary 进程）。我想更快地解析它。不使用ksoap2是否可以解析它？有什么想法吗？感谢您的建议。

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花开柳相依 2024-11-26 23:46:11

你说慢是什么意思？它执行 http 请求，然后解析响应。您必须在异步任务中执行此操作。内存使用情况将取决于您收到的响应。也许你的要求太多了。请参阅 wiki 了解如何调试！

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丑丑阿 2024-11-26 23:46:11

我对 KSoap2 还有另一个问题。不幸的是，ksoap2 库无法与我的网络服务一起使用。最后，我完成了默认的 http post。

我希望这对将来的人有帮助。

private String makeHttpRequest(){
        try{
            String request = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ns1=\"http://tempuri.org/\">"
                    +"<SOAP-ENV:Body>"
                    + "<ns1:Connect>"
                    + "<ns1:lstr_Login>xxxxx</ns1:lstr_Login>"
                    +"</ns1:Connect>"
                    +"</SOAP-ENV:Body>"
                    +"</SOAP-ENV:Envelope>";

            String soapAction = "http://tempuri.org/Connect"; //this would be your soapAction from wsdl

            StringEntity se = new StringEntity(request, HTTP.UTF_8);
            DefaultHttpClient client = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(new URI("http://xxxxxxxx.com/Storefront.asmx"));

            httpPost.addHeader("Content-Type", "text/xml; charset=utf-8");
            httpPost.addHeader("SOAPAction", soapAction);

            httpPost.setEntity(se);
            HttpResponse response = client.execute(httpPost);
            int responseStatusCode = response.getStatusLine().getStatusCode();
            Log.d(TAG, "HTTP Status code:"+responseStatusCode);
            if(responseStatusCode>=200 && responseStatusCode<300){
                //we got the success response from server. Now retrieve the value and go for usage.
                String responseStr = EntityUtils.toString(response.getEntity());
                //use this responseStr to parse with pullparsers or any
                Log.d("Response", "Response:: "+ responseStr);
                return responseStr;
            }
        }catch(Exception e){
            //Write the proper catch blocks for exceptions
            Log.e("Response Exception" , e.getMessage()+"",e);
        }
        return null;
    }

I have another problem with KSoap2. Unfortunately, ksoap2 library is not working with my webservices. So at last, I have done with default http post.

I hope this will help for someone in future.

private String makeHttpRequest(){
        try{
            String request = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ns1=\"http://tempuri.org/\">"
                    +"<SOAP-ENV:Body>"
                    + "<ns1:Connect>"
                    + "<ns1:lstr_Login>xxxxx</ns1:lstr_Login>"
                    +"</ns1:Connect>"
                    +"</SOAP-ENV:Body>"
                    +"</SOAP-ENV:Envelope>";

            String soapAction = "http://tempuri.org/Connect"; //this would be your soapAction from wsdl

            StringEntity se = new StringEntity(request, HTTP.UTF_8);
            DefaultHttpClient client = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(new URI("http://xxxxxxxx.com/Storefront.asmx"));

            httpPost.addHeader("Content-Type", "text/xml; charset=utf-8");
            httpPost.addHeader("SOAPAction", soapAction);

            httpPost.setEntity(se);
            HttpResponse response = client.execute(httpPost);
            int responseStatusCode = response.getStatusLine().getStatusCode();
            Log.d(TAG, "HTTP Status code:"+responseStatusCode);
            if(responseStatusCode>=200 && responseStatusCode<300){
                //we got the success response from server. Now retrieve the value and go for usage.
                String responseStr = EntityUtils.toString(response.getEntity());
                //use this responseStr to parse with pullparsers or any
                Log.d("Response", "Response:: "+ responseStr);
                return responseStr;
            }
        }catch(Exception e){
            //Write the proper catch blocks for exceptions
            Log.e("Response Exception" , e.getMessage()+"",e);
        }
        return null;
    }

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