PHP 中的点运算符

发布于 2024-11-19 23:08:47 字数 314 浏览 0 评论 0原文

我以为我已经知道字符串运算符 。 很好，直到今天我被问到了一个问题。这个问题看起来很简单：

echo 100...100;

乍一看我以为它会出现语法错误。但当我运行代码并看到结果时，我完全困惑了。结果是

1000.1

所以我想知道怎么会发生这种情况？

谢谢。

原文

I thought I've known the String Operator . well enough until I was asked a question about it today. The question looks quite simple:

echo 100...100;

At the first glance I thought it would make a syntax error. But when I ran the code and saw the result I was totally confused. The result is

1000.1

So I wonder how could this happen?

Thanks.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

雪化雨蝶 2024-11-26 23:08:47

像这样阅读：

(100.) . (.100)

因此它连接了 100 和 0.1。

Read it like this:

(100.) . (.100)

Thus it concats 100 and 0.1.

回复收藏 0 原文

清秋悲枫 2024-11-26 23:08:47

假设您的

echo 100...100;

意思是 PHP 的优点。 :)
该语句被理解为

100. . .100

相当于

100.0 . 0.1

<=>

'100' . '0.1'

<=>

'1000.1'

Assuming you meant

echo 100...100;

The reason for this is the beauty of PHP. :)
This statement is understood as

100. . .100

which is equivalent to

100.0 . 0.1

<=>

'100' . '0.1'

<=>

'1000.1'

回复收藏 0 原文

暖阳 2024-11-26 23:08:47

您可以将其读作 echo 100 。 0.1 。

回复收藏 0 原文

以为你会在 2024-11-26 23:08:47

实际上，只有在没有引号的情况下才有效：

echo "100...100";   100...100  << with quotes the . is just a char

echo 100 . 100;     100100     << two concatenated strings "100"

echo 100.100;       100.1      << 100.100 is just a number

echo 100...100;     1000.1     << what you asked

echo 100. . .100;   1000.1     << what PHP actually interprets

Actually, that only works without the quotes:

echo "100...100";   100...100  << with quotes the . is just a char

echo 100 . 100;     100100     << two concatenated strings "100"

echo 100.100;       100.1      << 100.100 is just a number

echo 100...100;     1000.1     << what you asked

echo 100. . .100;   1000.1     << what PHP actually interprets

回复收藏 0 原文

~没有更多了~