php比较关键字字符串

Question

我需要将这两个关键字字符串与 php.ini 进行比较。

$original_keywords = cat, dog, mouse

$possible_keywords_1 = "cat, dog, hamster";       
$possible_keywords_2 = "cat, sheep, goat"; 

我需要一个 php 脚本将数值“1”分配给第一个可能的字符串（1 个匹配），将“2”分配给第二个可能的字符串（2 个匹配）。有人可以帮我吗？

Answer 1

$original_keywords = array("cat", "dog", "mouse");
$possible_keywords1 = preg_split('/,\s*/', "cat, dog, hamster");
echo count(array_intersect($original_keywords, $possible_keywords1))

Answer 2

$original_keywords = "cat, dog, mouse";
$possible_keywords_1 = "cat, dog, hamster";
$possible_keywords_2 = "cat, sheep, goat";

// Put the input keywords into an array
$keywords = explode(', ', $original_keywords);

// Put all incoming keywords into one big array (you can add as many arrays
// as you want here)
$input = array_merge(
    explode(', ', $possible_keywords_1),
    explode(', ', $possible_keywords_2));

// Count how many times each keywords from $input appears
$count = array_count_values($input);

// Filter out from $count any keyword that is not present in $keywords
$result = array_intersect_key($count, array_flip($keywords));

查看实际操作。

Answer 3

您可以结合使用 explode 和 array_intersect

以下是开始的代码：

$possible_keywords_1_array = explode(",", $possible_keywords_1); 
$possible_keywords_2_array = explode(",", $possible_keywords_2); 
$matches = count(array_intersect($possible_keywords_1_array, $possible_keywords_2_array));