YQL 丢失 HTML 元素属性？

Question

<一href="http://developer.yahoo.com/yql/console/#h=select%20*%20from%20html%20where%20url=%27http://www.cbs.com/shows/big_bro其他/video/%27%20and%20xpath=%27//div%5B@id=%22cbs-video-metadata-wrapper%22%5D/div%5B@class=%22cbs-video-share%22%5D /a%27" rel="noreferrer">YQL 控制台链接

查询：

select * from html where url='http://www.cbs.com/shows/big_brother/video/' and xpath='//div[@id="cbs-video-metadata-wrapper"]/div[@class="cbs-video-share"]/a'

返回：

<?xml version="1.0" encoding="UTF-8"?>
<query xmlns:yahoo="http://www.yahooapis.com/v1/base.rng"
    yahoo:count="1" yahoo:created="2011-07-09T23:14:02Z" yahoo:lang="en-US">
    <diagnostics>
        <publiclyCallable>true</publiclyCallable>
        <url execution-time="146" proxy="DEFAULT"><![CDATA[http://www.cbs.com/shows/big_brother/video/]]></url>
        <user-time>163</user-time>
        <service-time>146</service-time>
        <build-version>19262</build-version>
    </diagnostics> 
    <results>
        <a class="twitter-share-button" href="http://twitter.com/share"/>
    </results>
</query>

应该返回类似于以下内容的内容：

    <results>
        <a href="http://twitter.com/share" data-url="http://www.cbs.com/shows/big_brother/video/2045825951/big-brother-episode-1" class="twitter-share-button"></a>
    </results>

如果我退出一级查询，它会完全删除该元素，我也可以使用该元素来获取我需要的数据。

Answer 1

我们现在有一个新的 html 解析器可以识别自定义属性。

添加 compat="html5" 以触发新的解析器。

例如：

select * from html where url = "http://mydomain.com" and compat="html5"