Android - 获取用户输入的整数

发布于 2024-11-19 04:25:13 字数 796 浏览 3 评论 0原文

我是一名新的 Android 开发人员。作为一个起始项目，我正在尝试创建一个基本的加法计算器。我有一个 EditText ，它应该接受输入（输入是一个字符串），并在按下 Button1 时将其转换为 int1 。当按下 Button2 时，它应该接受输入，将其转换为 int2，添加 int1 和 int2并将结果存储在 int ans 中，并将 EditText 的文本设置为 ans。但是，当我尝试使用 Integer.parseInt(et.getText().toString()) 时，出现错误并且应用程序强制关闭。谁能给我提供将这些字符串正确转换为整数的代码？谢谢。

static int fn = 0;
static int sn = 0;
static int ans = 0;
static int pro = 0;
//"+" Button Clicked//
if(pro == 0){
    fn = Integer.parseInt(entry.getText().toString());
    entry.setText("");
    pro++;
}else{
    //MessageBox Crap//

//"=" Button Clicked//
    sn = Integer.parseInt(entry.getText().toString());
    ans = fn + sn;
    entry.setText(ans);

原文

I'm a new Android developer. As a starting project, I'm trying to create a basic addition calculator. I have an EditText which is supposed to take the input (input is a string) and convert it to int1 when Button1 is pressed. When Button2 is pressed, it is supposed to take the input, convert it to int2, add int1 and int2 together and store the result in the int ans, and set the text of the EditText to ans. However, when I try to use Integer.parseInt(et.getText().toString()) I get an error and the app force closes. Could anyone provide me with the code to properly convert these Strings to integers? Thank you.

static int fn = 0;
static int sn = 0;
static int ans = 0;
static int pro = 0;
//"+" Button Clicked//
if(pro == 0){
    fn = Integer.parseInt(entry.getText().toString());
    entry.setText("");
    pro++;
}else{
    //MessageBox Crap//

//"=" Button Clicked//
    sn = Integer.parseInt(entry.getText().toString());
    ans = fn + sn;
    entry.setText(ans);

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