Lookaround 正则表达式来评估双方？
好吧，我有一个非常棘手的正则表达式问题。
我需要将以下字符串中的 + 号匹配并替换为空格，因此左侧的字符串必须成为右侧的字符串。
1: word+word = word word
2: word+++word = word + word
3: word.+word = word. word
4: word,+word = word, word
我已经成功地用这个来确定大部分的内容，它检查加号之前和之后的字符串：
(?<=[\w\.,])\+(?=[\w])
但是，我一次只能在 (2) 中确定一组相邻的加号：
(?<=[\w\.,\+])\+(?=[\w]) // gets the left plus sign
2: word+++word = word++ word
(?<=[\w\.,])\+(?=[\w\+]) // gets the right plus sign
2: word+++word = word ++word
在我当前的正则表达式中 ，疲惫不堪的状态下，我想知道是否需要将模式包装在更大的条件中，或者是否需要在环视中实现“任一”或“模式”。有正则表达式专家愿意尝试一下吗？
Ok, I have a pretty tricky regex problem.
I need to match and replace the + signs in the following strings with whitespace, thus the strings on the left must become the strings on the right.
1: word+word = word word
2: word+++word = word + word
3: word.+word = word. word
4: word,+word = word, word
I've managed to nail most of 'em with this, which checks for strings before and after plus signs:
(?<=[\w\.,])\+(?=[\w])
However, I can only nail one set of the adjacent plus signs in (2) at a time:
(?<=[\w\.,\+])\+(?=[\w]) // gets the left plus sign
2: word+++word = word++ word
(?<=[\w\.,])\+(?=[\w\+]) // gets the right plus sign
2: word+++word = word ++word
In my current regex be-frazzled state, I'm wondering if I need to wrap the pattern in a larger condition, or if I need to implement an either or pattern in the lookarounds. Any regex mavens out there care to give this a whirl?
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这应该适用于您的示例：
将其替换为空格。
示例：
输出：
This should work on your examples:
Replace that with spaces.
Example:
Outputs: