如何在 unix 上使用 shell 脚本替换 for...in 循环中的部分文件路径？

Question

需要很大的帮助。我完全被这个问题困住了。我正在循环（递归）目录中的所有文件并打印文件列表。比如：

# srcDir="input received from command line"
# tgtDir="input received from command line"

for listItem in `find ${srcDir}`
do
    if [[ -f ${listItem} ]]
    then
        echo ${listItem} # **** what to put here ****
    fi
done

打印列表时，我想将文件的路径从 srcDir 替换为 tgtDir。比如：

# let's assume that srcDir="/home/user"
# and tgtDir="/tmp/guest"
# srcDir has the following structure
file1.txt
dir1_1/file1a.txt
dir1_1/file1b.txt

# so the actual output of the script will be
/home/user/file1.txt
/home/user/dir1_1/file1a.txt
/home/user/dir1_1/file1b.txt

# but I want it to print as
/tmp/guest/file1.txt
/tmp/guest/dir1_1/file1a.txt
/tmp/guest/dir1_1/file1b.txt

我希望你明白了。请指教。

Answer 1

看起来像是 bash 字符串操作 的工作：

srcDir="/home/user"
tgtDir="/tmp/guest"
listItem="/home/user/file1.txt"
echo ${listItem/$srcDir/$tgtDir}