MySQL 查询 - 分组依据问题

发布于 2024-11-18 21:22:08 字数 1002 浏览 3 评论 0原文

以下 MySQL 查询生成一个 session_ids 和相关用法的列表。我想做的是将每个会话分组为一行,并显示最大的上传和下载。用户名可以多次重复,必须在会话中进行分组。

当我尝试使用分组依据时,并不总是选择最好的。

  SELECT USERNAME, ACCTSESSIONID,
         IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0) as TOTAL_UPLOAD,
         IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0) as TOTAL_DOWNLOAD
    FROM ACCOUNTING
   WHERE DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
ORDER BY USERNAME ASC, ACCTSESSIONID 

-

USERNAME    ACCTSESSIONID        TOTAL_UPLOAD   TOTAL_DOWNLOAD
kor1        SESSION232442        341594114     5671726599
kor1        SESSION232442        331306202     5571382940
kor1        SESSION232444        338083784     5609510490
kor1        SESSION454355        323367019     5451121083
kor2        SESSION943209        323132957     5450522047  
ran32       SESSION934082        323132957     5450522047
ran62       SESSIONA34324        9532356       5450523537

The following MySQL query produces me a list of session_ids and associated usage. What i would like to do is group each session into one row with the greatest upload and download displaying. There can be multiple repeats of a user name, it has to be grouped on the session.

When I try and use group by, the greatest is not always selected.

  SELECT USERNAME, ACCTSESSIONID,
         IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0) as TOTAL_UPLOAD,
         IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0) as TOTAL_DOWNLOAD
    FROM ACCOUNTING
   WHERE DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
ORDER BY USERNAME ASC, ACCTSESSIONID 

-

USERNAME    ACCTSESSIONID        TOTAL_UPLOAD   TOTAL_DOWNLOAD
kor1        SESSION232442        341594114     5671726599
kor1        SESSION232442        331306202     5571382940
kor1        SESSION232444        338083784     5609510490
kor1        SESSION454355        323367019     5451121083
kor2        SESSION943209        323132957     5450522047  
ran32       SESSION934082        323132957     5450522047
ran62       SESSIONA34324        9532356       5450523537

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评论(2

蓝梦月影 2024-11-25 21:22:08

为此,您应该使用 MIN()/MAX() 聚合函数:

SELECT USERNAME, ACCTSESSIONID,
     MAX(IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0)) as TOTAL_UPLOAD,
     MAX(IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0)) as TOTAL_DOWNLOAD
FROM ACCOUNTING
WHERE
    DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
GROUP BY
    USERNAME, ACCTSESSIONID
ORDER BY
    USERNAME ASC, ACCTSESSIONID 

有关 MySQL 中聚合函数的更多信息:http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html

You should use MIN()/MAX() aggregate functions for this:

SELECT USERNAME, ACCTSESSIONID,
     MAX(IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0)) as TOTAL_UPLOAD,
     MAX(IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0)) as TOTAL_DOWNLOAD
FROM ACCOUNTING
WHERE
    DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
GROUP BY
    USERNAME, ACCTSESSIONID
ORDER BY
    USERNAME ASC, ACCTSESSIONID 

More about aggregate function in MySQL: http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html

も星光 2024-11-25 21:22:08
  SELECT USERNAME, ACCTSESSIONID,
         MAX(IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0))
           AS TOTAL_UPLOAD,
         MAX(IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0))
           AS TOTAL_DOWNLOAD
    FROM ACCOUNTING
   WHERE DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
GROUP BY USERNAME ASC, ACCTSESSIONID 
ORDER BY USERNAME ASC, ACCTSESSIONID 

注1:除了IFNULL(),您还可以使用COALESCE()。它可能更可取,因为它可以有 2 个以上的参数,并且它也用于许多其他 RDBMS。

:而不是

DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'

注释 2:您可以使用

TIME_STAMP >= '2011-07-05'  AND  TIME_STAMP < '2011-07-06'

:无需为表中的每一行调用 2 个函数。

  SELECT USERNAME, ACCTSESSIONID,
         MAX(IFNULL(ACCTINPUTGW ,0) * POW(2,32) + IFNULL(ACCTINPUTOCT , 0))
           AS TOTAL_UPLOAD,
         MAX(IFNULL(ACCTOUTPUTGW,0) * POW(2,32) + IFNULL(ACCTOUTPUTOCT, 0))
           AS TOTAL_DOWNLOAD
    FROM ACCOUNTING
   WHERE DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'
GROUP BY USERNAME ASC, ACCTSESSIONID 
ORDER BY USERNAME ASC, ACCTSESSIONID 

Note 1: Instead of IFNULL(), you can also use COALESCE(). It may be preferable as it can have more than 2 arguments and it's also used in many other RDBMSs.

Note 2: Instead of:

DATE_FORMAT(FROM_UNIXTIME(TIME_STAMP), '%Y-%m-%d') = '2011-07-05'

you can use:

TIME_STAMP >= '2011-07-05'  AND  TIME_STAMP < '2011-07-06'

No need to call 2 functions for every row in the table.

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