java中如何获取自定义的synchronizedList？
我有一个扩展 ArrayList 的自定义列表 MyList，如下所示：
class MyList extends ArrayList<SomeParticularItem>{
[some methods...]
}
由于我对列表有并发读取和写入，我想同步它：
MyList mylist = (MyList) Collections.synchronizedList(new MyList());
这似乎没问题，.jar 已构建。然后，在运行时，我得到：
java.util.Collections$SynchronizedRandomAccessList cannot be cast to MyList
是否有更好的方法（有没有任何方法）来获取继承自某些 java.util.List 的列表的同步列表？
I have one customized list MyList that extends ArrayList, like this:
class MyList extends ArrayList<SomeParticularItem>{
[some methods...]
}
Since I have concurrent reads and writes to the list, I want to synchronize it:
MyList mylist = (MyList) Collections.synchronizedList(new MyList());
This seems to be fine, the .jar is build. Then, at runtime, I get:
java.util.Collections$SynchronizedRandomAccessList cannot be cast to MyList
Is there a better way (is there any way at all) to obtain a synchronized list of a list that inherits from some java.util.List?
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那么为什么不让 MyList 同步，或者简单地使用 List 接口
列表 mylist = Collections.synchronizedList(new MyList());
编辑：
您当然可以让 MyList 扩展 Vector，因为所有 Vectors 方法都已经同步，您可以节省一些工作。
Well why not make MyList synchronized, alternativly simply use the List interface
List mylist = Collections.synchronizedList(new MyList());
Edit:
You could of course let MyList extend Vector, since all of the Vectors methods are already synchronized you save some work.
最简单的方法是扩展
Vector而不是ArrayList。如果您想将其保留为ArrayList，您也可以自己同步MyList的方法。The easiest way to do it would be to extend
Vectorinstead ofArrayList. You could also synchronize the methods ofMyListyourself if you wanted to keep it as anArrayList.