如何使用 JSON URL

发布于 2024-11-18 18:37:37 字数 401 浏览 9 评论 0原文

我有一个 JSON 对象，看起来像这样：（以下链接是假的）

"results": {
    "urlStuff": [
        {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"},
        {"other_pic_url": "http:\/\/www.youtube.com\/outside\/kslkjfldkf\/234.jpg?v=7475646"}
    ]
}

或类似的东西。我的问题是，如果 URL 已经是字符串，为什么还要包含转义字符？我必须摆脱它们才能在 URL 上调用方法来获取图片。我错过了什么吗？我正在使用 Android 来拨打此电话。

谢谢，马特

原文

I've got a JSON object that looks something like this: (the following links are fake)

"results": {
    "urlStuff": [
        {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"},
        {"other_pic_url": "http:\/\/www.youtube.com\/outside\/kslkjfldkf\/234.jpg?v=7475646"}
    ]
}

or something to that effect. My question is, why do the urls have escape characters if they are already strings? I am having to get rid of them to make the method calls on the URL to get the pics. Am I missing something? I am using Android to make this call.

Thanks,
Matt

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风苍溪 2024-11-25 18:37:37

如果 URL 已经是字符串，为什么还要包含转义字符？

它们具有转义字符因为它们是字符串 - 具体来说，因为它们是 JSON 字符串，所以它们具有 JSON 字符串转义字符，并且将它们发送给您的实体决定使用该选项来转义斜线。有关发送实体为何做出此选择的更多信息，请参阅为什么 Groovy JSONBuilder 对 URL 中的斜杠进行转义？帖子。

我必须摆脱它们才能在 URL 上调用方法来获取图片。我错过了什么吗？

在将 JSON 字符串转换为 Java 字符串时，采用简单的方法，只需使用合适的 JSON 解析 API 即可自动删除 JSON 转义字符。 Android 有这样一个内置的 JSON 库可用。

package com.stackoverflow.q6564078;

import org.json.JSONObject;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;

public class Foo extends Activity
{
  @Override
  public void onCreate(Bundle savedInstanceState)
  {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"}
    String jsonInput = "{\"pic_url\": \"http:\\/\\/www.youtube.com\\/inside\\/kslkjfldkf\\/234.jpg?v=7475646\"}";
    Log.d("JSON INPUT", jsonInput);
    // output: {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"}

    try
    {
      JSONObject jsonObject = new JSONObject(jsonInput);
      String javaUrlString = jsonObject.getString("pic_url");
      Log.d("JAVA URL STRING", javaUrlString);
      // output: http://www.youtube.com/inside/kslkjfldkf/234.jpg?v=7475646
    }
    catch (Exception e)
    {
      throw new RuntimeException(e);
    }
  }
}

why do the urls have escape characters if they are already strings?

They have escape characters because they are strings -- specifically, because they are JSON strings they have JSON string escape characters, and the entity that sent them to you decided to use the option to escape the solidus. For more information on why the sending entity may have made that choice, see the Why does the Groovy JSONBuilder escape slashes in URLs? post.

I am having to get rid of them to make the method calls on the URL to get the pics. Am I missing something?

Take the easy route and just use a decent JSON parsing API to take care of automatically removing the JSON escape characters for you, when translating the JSON string into a Java String. Android has such a built-in JSON library available.

package com.stackoverflow.q6564078;

import org.json.JSONObject;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;

public class Foo extends Activity
{
  @Override
  public void onCreate(Bundle savedInstanceState)
  {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"}
    String jsonInput = "{\"pic_url\": \"http:\\/\\/www.youtube.com\\/inside\\/kslkjfldkf\\/234.jpg?v=7475646\"}";
    Log.d("JSON INPUT", jsonInput);
    // output: {"pic_url": "http:\/\/www.youtube.com\/inside\/kslkjfldkf\/234.jpg?v=7475646"}

    try
    {
      JSONObject jsonObject = new JSONObject(jsonInput);
      String javaUrlString = jsonObject.getString("pic_url");
      Log.d("JAVA URL STRING", javaUrlString);
      // output: http://www.youtube.com/inside/kslkjfldkf/234.jpg?v=7475646
    }
    catch (Exception e)
    {
      throw new RuntimeException(e);
    }
  }
}

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