Ajax 值未传输到 PHP
我有这个星级评定系统。当您单击星星时，它应该将一个值传递给函数。然后使用 AJAX 将其发布到外部 PHP 文件。唯一的问题是，当它到达 PHP 文件时，它是 null 或没有值。
我将尝试使用 AJAX 在警报框中回显 $_POST['vote'] 变量，它是空白的，因此它不会返回为“NULL”或“0”，它只是什么都没有。我不确定我在哪里丢失了该值，因为我可以一直跟踪它到 send() 函数。有人看出问题了吗？
HTML：
<style type="text/css">
#container{margin: 10px auto;width: 500px;height: 300px;background-color: gray;}
#starContainer{padding-top:20px;margin:0 auto;width:150px;}
.box{height:28px;width:30px;float:left;position:relative;z-index:5;cursor:pointer;}
.star{background-image:url('emptyStar.png');background-repeat:no-repeat;}
.starHover{background-image:url('goldStar.png');background-repeat:no-repeat;}
#voteBar{float:left;height:28px;background-color:#dbd923;position:relative;top:-28px;z-index:1;}
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('.box').hover(
// Handles the mouseover
function() {
$(this).prevAll().andSelf().addClass('starHover');
},
// Handles the mouseout
function() {
$(this).prevAll().andSelf().removeClass('starHover');
}
);
});
function Cast(vote)
{
if(window.XMLHttpRequest)
{
xmlhttp = new XMLHttpRequest();
}
else
{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function()
{
if(xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
alert(xmlhttp.responseText);
var json = JSON.parse(xmlhttp.responseText);
}
}
xmlhttp.open("POST", "process.php", true);
xmlhttp.send('vote=' + vote);
}
</script>
</head>
<body>
<div id="container">
<center>
<div id="starContainer">
<div class="box star" onclick="Cast(1)"></div>
<div class="box star" onclick="Cast(2)"></div>
<div class="box star" onclick="Cast(3)"></div>
<div class="box star" onclick="Cast(4)"></div>
<div class="box star" onclick="Cast(5)"></div>
<div id="voteBar"></div>
</div>
</center>
</div>
</body>
</html>
PHP：
<?php
$vote = $_POST['vote'];
$totalVoteValue = 0;
$amtVotes = 1;
$width = (($totalVoteValue + (($vote - $totalVoteValue) / $amtVotes)) / 5) * 150;
echo $width;
?>
I have this Star Rating system right. When you click on a star it should pass a value into the function. Then using AJAX it posts it to an external PHP file. The only problem is that when it gets to the PHP file it comes as null or no value.
I will try to echo the $_POST['vote'] variable in an alert box using AJAX and it is blank so it doesn't come back as "NULL" or "0" it's just nothing. I'm not sure where I'm losing the value because I can track it all the way to the send() function. Anyone see a problem?
HTML:
<style type="text/css">
#container{margin: 10px auto;width: 500px;height: 300px;background-color: gray;}
#starContainer{padding-top:20px;margin:0 auto;width:150px;}
.box{height:28px;width:30px;float:left;position:relative;z-index:5;cursor:pointer;}
.star{background-image:url('emptyStar.png');background-repeat:no-repeat;}
.starHover{background-image:url('goldStar.png');background-repeat:no-repeat;}
#voteBar{float:left;height:28px;background-color:#dbd923;position:relative;top:-28px;z-index:1;}
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('.box').hover(
// Handles the mouseover
function() {
$(this).prevAll().andSelf().addClass('starHover');
},
// Handles the mouseout
function() {
$(this).prevAll().andSelf().removeClass('starHover');
}
);
});
function Cast(vote)
{
if(window.XMLHttpRequest)
{
xmlhttp = new XMLHttpRequest();
}
else
{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function()
{
if(xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
alert(xmlhttp.responseText);
var json = JSON.parse(xmlhttp.responseText);
}
}
xmlhttp.open("POST", "process.php", true);
xmlhttp.send('vote=' + vote);
}
</script>
</head>
<body>
<div id="container">
<center>
<div id="starContainer">
<div class="box star" onclick="Cast(1)"></div>
<div class="box star" onclick="Cast(2)"></div>
<div class="box star" onclick="Cast(3)"></div>
<div class="box star" onclick="Cast(4)"></div>
<div class="box star" onclick="Cast(5)"></div>
<div id="voteBar"></div>
</div>
</center>
</div>
</body>
</html>
PHP:
<?php
$vote = $_POST['vote'];
$totalVoteValue = 0;
$amtVotes = 1;
$width = (($totalVoteValue + (($vote - $totalVoteValue) / $amtVotes)) / 5) * 150;
echo $width;
?>
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评论（2）
添加此内容可能会有所帮助（打开后发送之前）
adding this may help (before send after open)
你已经在使用jquery（如果我可以说是一个非常非常老的版本..），为什么不使用它内置的ajax处理程序呢？
http://api.jquery.com/jQuery.post/
You are already using jquery (a very very very old version if i may say..), why not use it's built in ajax handler?
http://api.jquery.com/jQuery.post/