在布局上绘制我自己的对象：子类化 gtk.drawable 的问题

发布于 2024-11-18 10:08:22 字数 852 浏览 2 评论 0原文

我想在布局上绘制自己的对象，所以我尝试子类化 gdk.drawable，

class link(gtk.gdk.Drawable):
  def __init__(self,comp1,comp2,layout):
      super(link, self).__init__()
      self.x1=comp1.xpos
      self.y1=comp1.ypos
      self.x2=comp2.xpos
      self.y2=comp2.ypos
      self.layout=layout

错误：

无法创建抽象（不可实例化）类型“GdkDrawable”的实例

我可以在链接对象的方法drawlink（）中使用layout.bin_window.draw_line（）子类化可绘制对象来做到这一点，但我无法创建自定义每个对象的图形上下文 gdk.gc ，我必须使用layout.get_style()，这对于我的所有链接都是相同的！

  def drawlink(self):
    gc = self.layout.get_style().fg_gc[gtk.STATE_NORMAL]
    gc.line_style=gtk.gdk.LINE_ON_OFF_DASH
    gc.line_width=6
    self.layout.bin_window.draw_line(gc,self.x1, self.y1, self.x2, self.y2)

这就是我想要子类化drawable的原因。如果我可以使用自定义 gc 而无需子类化可绘制对象或（窗口，像素图），那就太好了。

谢谢

原文

I want to draw my own object on a layout, so I'm trying to subclass gdk.drawable,

class link(gtk.gdk.Drawable):
  def __init__(self,comp1,comp2,layout):
      super(link, self).__init__()
      self.x1=comp1.xpos
      self.y1=comp1.ypos
      self.x2=comp2.xpos
      self.y2=comp2.ypos
      self.layout=layout

error:

cannot create instance of abstract (non-instantiable) type `GdkDrawable'

I can do it without subclassing drawable using layout.bin_window.draw_line() in a method drawlink() of my link object, but I'm not able to create a custom graphic context gdk.gc for each object and I have to use the layout.get_style() which will be the same for all my links!

  def drawlink(self):
    gc = self.layout.get_style().fg_gc[gtk.STATE_NORMAL]
    gc.line_style=gtk.gdk.LINE_ON_OFF_DASH
    gc.line_width=6
    self.layout.bin_window.draw_line(gc,self.x1, self.y1, self.x2, self.y2)

this is the reason I want to subclass drawable. if I can use a custom gc without subclassing drawable or(window, pixmap) it would be great.

Thanks

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