使用 while 循环计算数学常数 e

Question

我目前正在做一本书中的一项任务，要求我使用 while 循环计算数学常数 e。我很容易做到这一点，但是我在计算 e^x 时遇到了麻烦，而用户输入了 x 和准确度。我用于计算 e 的代码是：

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
int degreeOfAccuracy, x = 1;
long double e = 1;
cout << "Enter degree of accuracy of mathimatical constant e: ";
cin >> degreeOfAccuracy;
while (x <= degreeOfAccuracy)
{
      int conter = x;
      int intial = x;
      long double number = x;
      int counter = 1;
      while (conter > 1)
      {
             number = number*(intial-counter);
             counter++;
             conter--;
      }
      e += (1/number);
      x++;
}
cout << endl << "The mathematical constantr e is: " 
     << setprecision(degreeOfAccuracy) << fixed << e << endl;
system("pause");
return 0;
}

但是，当我尝试 e^x 时，以下代码返回了一个完全错误的值：

#include <iostream>
#include <iomanip>
using namespace std; 

int main()
{
int degreeOfAccuracy, x = 1, exponent;
long double e = 1;
cout << "Enter degree of accuracy of mathimatical constant e: ";
cin >> degreeOfAccuracy;
cout << "Enter the number of which you wish to raise to e: ";
cin >> exponent;
int temp = exponent;
while (x <= degreeOfAccuracy)
{
      exponent = temp;
      int conter = x;
      int intial = x;
      long double number = x;
      int counter = 1;
      while (conter > 1)
      {
             number = number*(intial-counter);
             counter++;
             conter--;
      }
      int counterr = 1;
      while (counterr < x)
      {
            exponent *= exponent;
            counterr++;
      }
      e += (exponent/number);
      x++;
}
cout << endl << "The mathematical constantr e is: " << setprecision(degreeOfAccuracy) << fixed << e << endl;
system("pause");
return 0;
}

有什么想法计算出了问题吗？

Answer 1

这行：

exponent *= exponent;

是错误的。应该是：

exponent *= temp;