链接列表让我的大脑变得混乱。我应该怎么做？
我正在尝试使用链表作为一种方式来积累我对 C 中指针的知识。所以，我写了一个小例子，但是当我编译它时，我收到一个错误，我似乎无法弄清楚：
In function 'append_node':
error: request for member ‘next’ in something not a structure or union
什么是正确的通过引用访问（或传递）结构的方法？
#include <stdio.h>
#include <stdlib.h>
struct node {
int val;
struct node *next;
};
static int append_node(int val, struct node **head) {
struct node *new_node;
new_node = (struct node *) malloc(sizeof(struct node));
new_node->val = val;
new_node->next = NULL
*(head)->next = new;
return 0;
}
int main() {
int i;
struct node *head;
struct node *curr;
head = NULL;
curr = (struct node *) malloc(sizeof(struct node));
for(i = 1; i <= 10; i++) {
append_node(i, &curr);
head = curr;
}
curr = head;
while(curr) {
printf("%d\n", curr->val);
curr = curr->next ;
}
return 0;
}
任何帮助都会很棒！
I'm attempting to use linked lists as a way to buildup my knowledge of pointers in C. So, I wrote a small example but when I compile it I'm getting an error I can't seem to figure out:
In function 'append_node':
error: request for member ‘next’ in something not a structure or union
What's the proper way to access (or pass) a structure by reference?
#include <stdio.h>
#include <stdlib.h>
struct node {
int val;
struct node *next;
};
static int append_node(int val, struct node **head) {
struct node *new_node;
new_node = (struct node *) malloc(sizeof(struct node));
new_node->val = val;
new_node->next = NULL
*(head)->next = new;
return 0;
}
int main() {
int i;
struct node *head;
struct node *curr;
head = NULL;
curr = (struct node *) malloc(sizeof(struct node));
for(i = 1; i <= 10; i++) {
append_node(i, &curr);
head = curr;
}
curr = head;
while(curr) {
printf("%d\n", curr->val);
curr = curr->next ;
}
return 0;
}
Any help would be great!
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评论（3）
我可以假设您在这一行遇到错误吗？
我认为你需要做一个小小的改变：
由于
head是一个指向指针的指针，当你取消引用它时，你会得到一个指针。->next对该指针进行操作。Can I assume you're getting the error on this line?
I think you need to make one trivial change:
Since
headis a pointer to a pointer, when you dereference it you get a pointer. The->nextoperates on that pointer.两个问题：
末尾少了一个
;改为
，
Two problems:
There is a missing
;at the end ofand change
to
请尝试以下操作：
将
**head转换为*head，然后在其上调用成员。Try this instead:
Turn
**headto*headand then call members on it.